==== TABLE OF CONTENTS ====
A-Pivotal-Amplitude-for-Voronoi-Percolation-from-Cardys-Formula//00-introduction.tex
A-Pivotal-Amplitude-for-Voronoi-Percolation-from-Cardys-Formula//01-inputs.tex
A-Pivotal-Amplitude-for-Voronoi-Percolation-from-Cardys-Formula//02-annuli.tex
A-Pivotal-Amplitude-for-Voronoi-Percolation-from-Cardys-Formula//03-spectrum.tex
A-Pivotal-Amplitude-for-Voronoi-Percolation-from-Cardys-Formula//04-shape.tex
A-Pivotal-Amplitude-for-Voronoi-Percolation-from-Cardys-Formula//05-transfer.tex
A-Pivotal-Amplitude-for-Voronoi-Percolation-from-Cardys-Formula//06-amplitude.tex
A-Pivotal-Amplitude-for-Voronoi-Percolation-from-Cardys-Formula//lobes.tex
A-Pivotal-Amplitude-for-Voronoi-Percolation-from-Cardys-Formula//paper.tex
A-Pivotal-Amplitude-for-Voronoi-Percolation-from-Cardys-Formula//references.tex
===========================
==== BEGIN A-Pivotal-Amplitude-for-Voronoi-Percolation-from-Cardys-Formula//00-introduction.tex ====
\section{Introduction}\label{sec:introduction}
Let $\eta_\eps$ be a homogeneous Poisson process in $\R^2$ of intensity
$\eps^{-2}$. Color its Voronoi cells independently black or white, each
with probability $1/2$. For a bounded quadrilateral $Q$, a black crossing
means a connected black-cell path inside the closed quadrilateral joining
its two specified opposite sides. The cells are those of the full-plane
tessellation: the process is not resampled at the boundary, and no
boundary sites are wired together.
A nucleus is \emph{color-pivotal} for this event if changing only its cell's
color changes whether the crossing occurs. Write $N_\eps(Q)$ for the
number of such nuclei, including nuclei outside $Q$ when their cells
meet $Q$, and set $N_\eps=N_\eps([0,1]^2)$ for a left-to-right crossing.
All expectations below average both the Poisson geometry and the colors.
\begin{assumption}[Scalar Cardy limit]\label{ass:cardy}
For every bounded Jordan quadrilateral $Q$ with four distinct marked
boundary points, the critical crossing probability converges, as
$\eps\downarrow0$, to Cardy's conformally invariant value.
\end{assumption}
Here a Jordan quadrilateral is a Jordan domain with four marked boundary
points in cyclic order and a specified pair of opposite boundary arcs.
In the upper half-plane normalization with marked points $0,x,1,\infty$,
$00$, and constants $C,c>0$ such
that, for $b_*\le r0$, in the mesh-first limit the probability of
four bulk arms with any specified color order is at most
$C(r/s)^{1+c_0}$, and that of six bulk arms with any specified color
order is at most $C(r/s)^{2+c_0}$. Three free arms at a regular
boundary, measured in a conformal chart, have an upper bound with
exponent strictly larger than one.
\end{enumerate}
\end{proposition}
For precise locators, part~(i) uses Proposition~2.4, Lemma~2.5, and
Proposition~4.5 of~\cite{V}; part~(ii) uses Proposition~3.1 and
Lemmas~3.4--3.7; part~(iii) uses Lemmas~2.7, 2.8, and~2.11.
The free boundary-arm estimate in Lemma~2.11 has exponent $4/3$.
``Free'' means that the arms use the independent fair interior sites,
not the sites in the prescribed base arc.
We emphasize two domain qualifications. First, a boundary chart must
converge uniformly on its closure, have no constant boundary subarc,
and project injectively on the compact bank interval where the
estimate is used. Separate prime-end banks need not have disjoint
physical projections. The local estimate applies in an annulus by
choosing a small graph disk patch with one side on that bank and the
remaining sides in the interior. These are Jordan approximations;
reflection in the parameter coordinate gives bounded distortion on
smaller patches. Second, product colors are conditional on the graph.
After an exploration, its remaining colors are fresh, but a
remaining-domain theorem can be used only after its geometric
hypotheses have been established. We never infer uniform convergence
after conditioning on arbitrary atypical explored colors. The uniform
operator estimate in Section~\ref{sec:transfer} will instead use
independent core variables and bounds on the signed weights.
We use the site triangulation of the Voronoi tiling from~\cite{V}.
Its faces are triangles, drawn through the tiling rather than required
to have straight edges. An interface strand, or \emph{wall}, passes
through a triangle between its two heterochromatic edges. Inside a
screened collar, simple site cycles approximate circles in curve
order. They may be constructed by following narrow strips and
retaining simple cuts; same-boundary chords on the domain-facing side
can be shortcut while retaining the specified inner region. Auxiliary
uniform angular choices, if needed, preserve rotation invariance.
All transfer cuts in this paper lie in the bulk. Their incident cells
and stars stay away from the quad boundary, where site connectivity
and cell connectivity could otherwise require additional care.
At the actual quad boundary, we retain the original closed-cell event
and use the necessary-arm estimates just stated. Null nongeneric
geometries, and null sets of insertion locations in integrals, are
discarded throughout.
\subsection{Calibration and the preliminary exponent}
Let $S_\eps$ be the probability that a site inserted at the center of
$Q_0=[-1,1]\times[-1/2,1/2]$ is color-pivotal for its left-to-right
crossing in intensity $\eps^{-2}$. Equivalently, $S_\eps$ is the
expectation of the black-forced crossing indicator minus the
white-forced crossing indicator for that site. Set
\[
m_\eps=\eps^{-2},\qquad
q_\eps=\bigl(\E N_\eps(Q_0)\bigr)^{-1},\qquad
f(R)=S_{1/R}.
\]
The last equality agrees by Euclidean scaling with the unit-intensity
definition in the introduction.
\begin{proposition}[Calibration]\label{in:calibration}
There are constants $c,B\in(0,\infty)$ such that
\begin{equation}\label{in:calibration-eq}
m_\eps q_\eps S_\eps\longrightarrow c,
\qquad q_\eps\E N_\eps\longrightarrow B.
\end{equation}
Moreover,
\begin{equation}\label{in:comparison}
f(R)\asymp A(b_*,R).
\end{equation}
\end{proposition}
The limits are precisely the single-time Poisson specialization of
Lemmas~7.1 and~7.2 of~\cite{V}, called ``Common calibration'' and
``The prescribed normalization.'' The signed color weight at the
inserted site is $\delta_1-\delta_0$; crossing monotonicity identifies
its expectation with $S_\eps$. The comparison follows from the local
pivotal bounds and the square-to-site calibration in Sections~2 and~6
of~\cite{V}. These inputs do not assert that
$R^{5/4}f(R)$ converges.
\begin{lemma}[Exponent without an amplitude]\label{in:exponent}
Under Assumption~\ref{ass:cardy},
\begin{equation}\label{in:exponent-eq}
f(R)=R^{-5/4+o(1)}\qquad(R\to\infty).
\end{equation}
\end{lemma}
\begin{proof}
Force all cells meeting a central square of radius $h$ in $Q_0$
first black and then white, and denote the difference of crossing
probabilities by $D_\eps(h)$. Proposition~4.5 of~\cite{V} gives,
for each fixed small $h>0$, a common limit of this quantity in the
Voronoi and triangular models. The upper arm bound and
\cite[Lemma~6.1]{V}, ``A square can transmit a pivotal change,''
compare $D_\eps(h)$ with the four-arm probability from radius $h$
to radius $1$, with constants uniform in small $h$, after taking
the mesh limit. The corresponding triangular four-arm probabilities
have exponent $\lambda=5/4$ by~\cite{SW}.
Fix $\eta>0$. For an arbitrarily large but fixed ratio $L=1/h$,
these comparisons and qualitative convergence imply, for all
sufficiently large $r$ depending on $L$,
\[
c_\eta L^{-\lambda-\eta/3}
\le A(r,Lr)\le C_\eta L^{-\lambda+\eta/3}.
\]
Choose $L$ so large that both these constants and the constants in
\eqref{in:quasimult} are absorbed by an additional factor
$L^{\eta/3}$. Only after fixing this $L$ choose a starting radius
above the convergence threshold. Iterating over radii $r,Lr,L^2r,
\ldots$ gives four-arm bounds with exponents between
$\lambda-\eta$ and $\lambda+\eta$. The bounded initial range and
the final incomplete ratio change only the multiplicative constants,
by \eqref{in:power} and \eqref{in:quasimult}. Equation~\eqref{in:comparison}
then yields
$C_\eta^{-1}R^{-\lambda-\eta}\le f(R)\le C_\eta R^{-\lambda+\eta}$.
Letting $\eta\downarrow0$ proves the lemma.
\end{proof}
We will henceforth write $\lambda=5/4$. The remaining task is to
replace the $o(1)$ in this exponent by convergence of the multiplicative
coefficient. The next two analytic sections identify which annular
symmetries make that improvement possible.
==== END A-Pivotal-Amplitude-for-Voronoi-Percolation-from-Cardys-Formula//01-inputs.tex ====
==== BEGIN A-Pivotal-Amplitude-for-Voronoi-Percolation-from-Cardys-Formula//02-annuli.tex ====
\section{Four-interface transmission in an annulus}
\label{sec:annuli}
The continuum quantity used below is the probability that four interfaces
cross an annulus from one boundary component to the other. Its existence
does not follow by applying the scalar Cardy hypothesis directly to a
multiply connected domain. We establish it from the Jordan-domain inputs
of \cite{V}. We also allow the boundary banks produced by stopped
explorations: a bank is viewed with its access from the domain, so distinct
banks may touch in the plane without being identified.
\subsection{Connection states and two caps}
Use the site triangulation drawn through the Voronoi tiling, with interface
strands drawn across the heterochromatic edges of its triangular faces.
These strands will be called \emph{walls}. On a simple site cycle with
known colors, a \emph{run} is a maximal consecutive set of sites of one
color, and a \emph{switch} is the edge between consecutive runs. Filling
the disk bounded by the cycle determines a noncrossing pairing of its switches by
walls. The pairing, together with the run colors, determines connectivity
between boundary sites. Closed walls need not be recorded. We call this
pairing the connection state on the cycle.
Suppose each boundary component of a graph annulus has four switches and
four alternating prescribed runs. All remaining sites have independent
fair colors. Let $\mathcal T$ be the event that all four outer wall ends
reach the inner boundary. There are two possible connection states in a
disk filling the inner cycle: the cap joining its two black runs, denoted
$\mathsf b$, and the cap joining its two white runs, denoted $\mathsf w$.
These are formal planar caps; no random colors are sampled in them. Write
$H_{\mathsf b}$ and $H_{\mathsf w}$ for the indicators that the two outer
black runs are connected after the corresponding cap is attached.
Figure~\ref{fig:annular-caps} shows the two cap states when all four
walls are transmitted.
\begin{lemma}[The cap identity]\label{an:caps}
For every coloring of the annulus,
\begin{equation}\label{an:cap-equation}
H_{\mathsf b}-H_{\mathsf w}=\mathbf 1_{\mathcal T}.
\end{equation}
Consequently the signed difference between the two inner cap states is
transferred to the same signed difference at the outer cycle, multiplied
by the indicator of four-interface transmission. The identity remains
valid under composition across several cycles.
\end{lemma}
\begin{proof}
Walls in a triangulation neither branch nor cross. If fewer than four
inner ends are connected to outer ends, the wall pairing visible from the
outer cycle is independent of the inner cap: there is no choice of pairing
on zero or two surviving ends. Thus the left side of
\eqref{an:cap-equation} is zero. If all four are transmitted, their cyclic
order is preserved, with any possible winding retained. The intervening
monochromatic bands carry black connectivity to black connectivity and
white connectivity to white connectivity. Hence $H_{\mathsf b}=1$ and
$H_{\mathsf w}=0$. This is also the usual Hex duality proof after each run
is contracted to a vertex. Composing the planar pairings proves the last
assertion; any closed walls created in the composition have weight one.
\end{proof}
\begin{figure}[tb]
\centering
\begin{tikzpicture}[scale=0.87,line cap=round]
\foreach \a/\txt in {0/{Black cap: $H_{\mathsf b}=1$},6/{White cap: $H_{\mathsf w}=0$}} {
\begin{scope}[xshift=\a cm]
\draw[gray] (0,0) circle (1.85);
\draw[gray] (0,0) circle (.76);
\draw[very thick] (45:1.85) arc (45:135:1.85);
\draw[very thick] (225:1.85) arc (225:315:1.85);
\draw[very thick] (45:.76) arc (45:135:.76);
\draw[very thick] (225:.76) arc (225:315:.76);
\foreach \t in {45,135,225,315} {
\draw[blue!65!black,thick] (\t:.76)--(\t:1.85);
\fill (\t:.76) circle (1.4pt);
\fill (\t:1.85) circle (1.4pt);
}
\node at (0,2.12) {$B$};
\node at (0,-2.12) {$B$};
\node at (-2.12,0) {$W$};
\node at (2.12,0) {$W$};
\node[align=center] at (0,-2.65) {\txt};
\end{scope}
}
\draw[blue!65!black,thick] (45:.76) .. controls (.20,.25) and (.20,-.25) .. (315:.76);
\draw[blue!65!black,thick] (135:.76) .. controls (-.20,.25) and (-.20,-.25) .. (225:.76);
\begin{scope}[xshift=6cm]
\draw[blue!65!black,thick] (45:.76) .. controls (.25,.20) and (-.25,.20) .. (135:.76);
\draw[blue!65!black,thick] (225:.76) .. controls (-.25,-.20) and (.25,-.20) .. (315:.76);
\end{scope}
\end{tikzpicture}
\caption{The two cap pairings when all four walls are transmitted.
Blue curves are walls; thick black boundary arcs are black runs, and the
other runs are white. The cap changes the outer black connection bit by
one. The straight, unwound walls are schematic: the identity permits
winding and does not prescribe a pairing of numbered inner and outer
switches.}\label{fig:annular-caps}
\end{figure}
\subsection{The boundary convergence used below}
For $p>0$ let
\[
\mathbb A_p=\{e^{-p}<|z|<1\}.
\]
Thus $p=\log(R/r)$ for a round annulus with radii $r0$, and a free arm from a
shrinking neighborhood to a fixed scale has probability tending to zero.
The word \emph{free} excludes prescribed sites and cap wires. The local
bank versions, including arms approaching the bank arbitrarily closely,
are those of \cite[Section 2, ``Cardy tests in a boundary chart'' and
``Free boundary-arm bounds'']{V}.
\begin{lemma}[Continuity under boundary motion]\label{an:motion}
For a sequence with admissible boundary convergence, move either cycle
slightly into the annulus in round coordinates, and move its switches
slightly with it. Couple all unchanged free colors. The probability
that either capped connection test changes tends to zero as the size of
the motion tends to zero, after taking the mesh limit. The assertion also
holds for small piecewise smooth motions in spare space around an inset
annulus. It is uniform along any convergent sequence of admissible data
with distinct limiting switches. More precisely, if $H_n$ and
$H_{n,\delta}$ are either capped indicators before and after a motion of
size at most $\delta$, preserving the run order and its labels away from
the moving switches, then
\begin{equation}\label{an:motion-limit}
\lim_{\delta\downarrow0}\limsup_{n\to\infty}
\Pp(H_n\ne H_{n,\delta})=0.
\end{equation}
\end{lemma}
\begin{proof}
First the mesh in annular coordinates tends to zero. Otherwise a
connected cell or triangle portion of vanishing physical diameter would
have preimages with a subsequential nontrivial continuum limit on which
$\phi$ is constant. Such a continuum cannot meet the interior, where
$\phi$ is one-to-one, and cannot lie on the boundary, whose finitely many
simple arcs contain no constant interval. Here graph portions, rather
than whole cells crossing the domain boundary, are used.
Remove small coordinate neighborhoods of the switches and of the
finitely many joins of simple bank arcs. On each remaining compact bank
interval, use disk patches whose boundary consists of that bank and cuts
strictly inside the annulus. Their physical boundaries are Jordan and
their graph approximations converge in curve order. Their uniformizing
coordinates agree, with fixed-scale margins, with the annular coordinates;
reflection in the limiting round bank controls distortion on smaller
patches. Thus the local boundary-arm estimates of \cite{V} apply on these
patches even when another prime-end bank has the same physical image.
Cover these intervals by $O(s^{-1})$ coordinate disks of radius $s$.
Implement a motion much smaller than $s$ by successively replacing bank
intervals, with tapered ends. At graph level choose short transverse
joins in disjoint narrow strips from the old cycle to its replacement.
Substitute the intervals in cyclic order, retaining the old cycle off the
interval currently being changed and erasing the joins once the whole
cycle is replaced. The graph approximation in curve order ensures that
these are simple cuts. Each join has the same constant color as its run.
Moves containing switches or bank joins are instead included in the
exceptional neighborhoods. Two nearby nonnested contours can be
compared through a common slightly inset contour.
Consider one ordinary move on a black bank. If a capped connection test
changes, choose a winning black connection in one test and a winning
dual white connection in the other. Contract the prescribed runs and
use the same cap in both tests. Purely wired connections do not change,
so a free segment of a winning path must meet the support of the move.
The test neighborhood avoids every other run and mark. The white path
has two free branches leaving that neighborhood. At least one black
branch must also leave freely: a black branch already reaching the same
prescribed run outside the moved interval could be joined there without
the local change. Taking simple paths after contraction gives disjoint
white branches, and the opposite-colored black branch is disjoint from
them in the common fair region. This gives three free arms in a slightly
shifted half-patch, with fixed-factor margins. The same argument applies
with the colors interchanged. Forced sites on intermediate cuts are not
counted as free arms.
For any fixed larger chart scale, the mesh-first bound for a single disk
is $O(s^{1+\eta})$. The union over $O(s^{-1})$ disks therefore costs
$O(s^\eta)$. The number of exceptional neighborhoods is fixed. A change
there requires a fair arm approaching from positive parameter distance:
connections already provided by the same run or by the cap do not
change. This arm has positive physical diameter, uniformly after fixing
its outer parameter scale, by the no-continuum-fiber observation above.
The ordinary physical one-arm bound consequently makes the exceptional
cost tend to zero, including at a contact between different accesses.
One may move each exceptional neighborhood as a single piece, so this
cost is not multiplied by the number of ordinary intervals.
First take the mesh limit, then make the ordinary motions small compared
with $s$, then let $s$ tend to zero, and finally shrink the exceptional
neighborhoods. This proves the assertion. The same proof with moving
marks, or with a moving round radius, proves the stated continuity.
\end{proof}
After applying Lemma~\ref{an:motion}, all prescribed banks can be placed
on smooth contours strictly inside the parameter annulus, with spare
space on both sides. There are still two separate issues: joint ordinary
crossings must have a conformally invariant annular law, and those
crossings must determine the capped tests. We address them in that order.
\begin{lemma}[Ordinary crossings in an annular open set]
\label{an:ordinary}
In an annular open set compactly inside the parameter annulus, the joint
limiting law of any countable collection of regular ordinary quad tests
is conformally invariant. The tests may be chosen from a countable dense
family of polygon or piecewise smooth quads with positive margins.
\end{lemma}
\begin{proof}
On every strict Jordan disk patch the joint law is the critical triangular
percolation law by \cite[Sections 3--4]{V}. This law is conformally
invariant; see \cite[Theorems 1 and 7]{CN} and the quad-crossing
formulation in \cite[Section 2.3]{GPS}. Scalar Cardy sandwiches identify smooth images of polygon
tests and nearby graph crossing conventions with the same limit.
Choose a finite-length smooth cut opening the annulus. Any finite
collection of tests compactly contained off the cut fits in a strict
Jordan disk, so its joint law agrees in the physical domain and in the
conformal chart. To recover tests meeting the cut, use the
Schramm--Smirnov gluing theorem
\cite[Theorem 1.19 and Proposition 4.1]{SS}, only in strict Jordan disk
patches. For the critical triangular crossing law, the crossing of a
regular quad in such a patch is measurable, modulo null sets, with
respect to countably many tests avoiding the finite smooth cut in that
patch. Its hypotheses hold here: independence in the discrete model,
RSW, one-arm decay, and a four-arm exponent strictly greater than one.
Regular continuity tests may be used throughout, by Cardy sandwiches.
Each required quad meeting the annular cut has a slightly larger Jordan
disk neighborhood inside the annulus. The recovering measurable rule
in that neighborhood is the same in the chart and in its image, since
their whole disk laws already agree. All recovering tests belong to the
common countable off-cut family. Hence the recovered crossings have the
same joint law as well. This proves the assertion. White crossings are
included by Hex duality and continuity. No gluing assertion along a rough
slit is used.
\end{proof}
\begin{proposition}[The annular transmission limit]\label{an:limit}
For every sequence with admissible boundary convergence, the probability
of $\mathcal T$ has a limit depending only on the round data $(p,x,y)$ and
the choice of inner colors. Denote these limits by
\[
T^+(p,x,y),\qquad T^-(p,x,y).
\]
They are continuous for $p>0$ and distinct switches. The same convergence
holds for each capped connection probability. In particular, it applies
to random remaining domains whenever, conditional on their geometry and
explored boundary, their interior colors are fresh and their marked
domains have admissible convergence almost surely in a subsequential
coupling. In that case the difference between the conditional
transmission probability and $T^\pm$ evaluated at the actual annular
conformal data tends to zero in mean absolute value.
\end{proposition}
\begin{proof}
By Lemma~\ref{an:motion}, it suffices first to consider smooth inset
annuli with spare space. We show that ordinary quad crossings determine
the limiting value of each capped black connection test. Sample fair
colors throughout a slightly larger annular neighborhood in that spare
space, overriding them on prescribed runs only when evaluating a capped
test. Ordinary tube tests use the fair colors. Compare two
candidate sequences, one of which may be in round coordinates. Couple
their countable ordinary crossing vectors through the common limiting
law of Lemma~\ref{an:ordinary}. Along further subsequences include the
cap indicators in the coupling; the curve tightness proved below also
allows the chosen winning paths to be included. The two limiting
collections are coupled to have the same ordinary crossing vector.
Fix a small \emph{favorable} perturbation of the black test in the second
sequence. Move black banks into the annular fluid and extend their runs
slightly past the old switches; retreat white banks from the old fluid.
Use positive slacks and taper the motions within the old white
intervals, putting each new switch on the retreated part. Thus every old
black attachment lies behind a new black bank, the new white banks are
positively separated from the old fluid, and any removed fluid is in
separate collars of the expanded black runs. All these choices take
place in the spare space.
On a positive configuration in the first sequence, contract each
prescribed run and attach the cap edge when it is black. Take an
outermost simple winning path between the two outer black terminals.
For example attach an external terminal edge and take the appropriate
boundary of the union of cycles containing it. Contracting connected
boundary runs and attaching the cap preserves the planar embedding.
The resulting path has no bypass on its chosen exterior side. Since it
visits each contracted run at most once, it decomposes into a bounded
number of free black segments joining different runs, together with
wired or cap joins. Crop their endpoints by a vanishing graph distance
if they end adjacent to a wire.
We recall why these free segments admit simple limiting curves. Many
oscillations across an annulus supply many disjoint free arms; BK and
one-arm decay bound their probabilities. Successive-excursion
compactness therefore gives tightness in the curve metric. A bulk
self-contact with two positive excursions would give four black
traversals. In two gaps on the no-bypass side, intermediate transverse
cuts and Hex duality give two additional white traversals: a black
transverse crossing would instead be a bypass. The six arms are
disjoint after fixed-factor crops, also for backtracking pieces.
The mesh-first six-arm exponent greater than two excludes such contacts
by a covering argument. At a smooth boundary bank, a repeated visit to
the same point gives at least three free traversals, including when one
of the visits is an endpoint; the boundary exponent greater than one
excludes these repeated visits. A single tangential bank contact need
not be excluded: the favorable perturbation accommodates it. At the finitely
many switches one free arm suffices. These are precisely the local
no-bypass and free-segment arguments of \cite[Section 4, ``Free segments
of a terminal path'']{V}. Contracted runs do not change the bulk argument,
whose working annulus avoids them. Constant pauses may be removed.
In a subsequential coupled representation, fix the favorable displacement
and then crop each limiting free segment a small positive amount at its
ends, keeping the new endpoints strictly behind the expanded black
banks. A cropped endpoint may still lie on an old bank; the ambient
tube may straddle that bank within the spare space. This positive crop is distinct from the vanishing
graph crop used to remove incidences to a wire. Surround the cropped
simple segment by a thin Jordan tube, with end caps in those endpoint
neighborhoods. The approximating free graph segments supply ordinary
fair-color crossings of this ambient tube. The tube can be approximated with positive margins by a quad
from the countable ordinary test family. Its crossing occurs in the
first sequence, and hence in the second for all sufficiently large
indices in the coupling. The witnesses may be chosen from the countable
family after taking the subsequential limit; coordinatewise convergence
still applies to each of the finitely many chosen witnesses.
Clip these transferred crossings when they hit the new black banks.
Excursions outside the new fluid can only lie in the collars now wired
black. They can be shorted through the corresponding run, and collars
of different black banks are separated. This operation also handles
arbitrarily many backtracks: at graph level every passage between a
removed collar and the fluid meets its boundary cycle. The transferred
tubes, together with the unchanged cap or wire joins, therefore give a
winning black connection in the favorably perturbed second test.
Apply this comparison to subsequences realizing the upper and lower
limits of the unperturbed cap probabilities. The upper limit of the
first is bounded by the lower limit of the second plus its boundary-motion
error. Remove the favorable perturbations using Lemma~\ref{an:motion}
and reverse the roles of the sequences. Their upper and lower limits
coincide. This proves convergence and conformal invariance of each cap
test on inset annuli. Taking the inset size to zero proves the same
assertions under Definition~\ref{an:admissible}. The cap identity gives
the transmission limit. Allowing the marks and round radii to move in
the same comparison proves continuity in $(p,x,y)$.
Finally consider random remaining domains under the stated coupling.
For almost every convergent domain realization, the deterministic
statement applies to its fresh product-color law; continuity identifies
the same limit for $T^\pm$ at the actual conformal data. All probabilities
are bounded by one, so bounded convergence gives convergence in mean
absolute value. This conclusion does not assert a uniform conditional
estimate over arbitrary atypical explored boundaries.
\end{proof}
\begin{lemma}[Collisions and symmetries]\label{an:collision}
The functions $T^\pm$ extend continuously by zero when switches collide
on either boundary, uniformly for $p$ in compact subsets of $(0,\infty)$.
They are invariant under simultaneous rotation of $x$ and $y$ and under
global color reversal. Cyclic relabeling by one switch in either tuple
interchanges $T^+$ and $T^-$.
\end{lemma}
\begin{proof}
\leavevmode\clubpenalty=10000
If two consecutive switches coalesce, four-interface transmission
requires a fair arm from their intervening shrinking run to the other
boundary. This arm cannot use another prescribed run: it lies between
the two corresponding transmitted walls. A mesh-first one-arm bound,
with a fixed outer scale and then a shrinking inner scale, proves
vanishing. The bound does not depend on the positions of the other
switches and therefore also covers simultaneous collisions.
Conformal invariance gives simultaneous rotational invariance, and
fair colors give global color symmetry. Moving the first switch to the
next switch reverses the alternating run labels on that component.
By the defining convention, this interchanges the two inner prescriptions.
\end{proof}
==== END A-Pivotal-Amplitude-for-Voronoi-Percolation-from-Cardys-Formula//02-annuli.tex ====
==== BEGIN A-Pivotal-Amplitude-for-Voronoi-Percolation-from-Cardys-Formula//03-spectrum.tex ====
\section{The spectrum of four-interface transmission}
\label{sp:section}
\label{sec:spectrum}
We now estimate the limiting transmission probabilities
$T^\pm(p,x,y)$ of Section~\ref{sec:annuli} when the modulus $p$ is large.
There are two different conclusions. The leading term separates into an
inner factor and an outer factor. The signed difference $T^+-T^-$ has
additional decay, and averaging the rotation of one end improves that
decay beyond exponent $2$. This last improvement will make the response
to a fair Poisson insertion integrable over the plane.
\subsection{The modulus equation}
The space of four cyclically ordered, labeled angles is
\[
\mathcal C=
\{w\in\R^4:w_10$ and every fixed finite derivative order $k$,
the vector field $B_p$ extends smoothly across angle collisions and
\[
\|B_p\|_{C^k}\le C_{k,p_0}e^{-p}\qquad(p\ge p_0).
\]
It is equivariant under permutations within either tuple, common
rotations, and cyclic relabelings. In particular, its normal component
at every collision face is zero.
\end{proposition}
\begin{proof}
We first derive a local equation with just one switch active. Write the
annulus as the cylinder $0<\operatorname{Im}z0$. For either transmission function, or its sum or difference,
the transformed solution satisfies
\begin{equation}\label{sp:uniform-smoothing}
\|W(p)\|_\infty+\operatorname{Lip}(W(p))\le C_{p_0}
\qquad(p\ge p_0+2).
\end{equation}
The semigroup $P_t$ of $D$ is symmetric on $L^2(\mu)$ and, for every
$q>1$, maps $L^q(\mu)$ to bounded functions at every fixed positive
time. At unit time the evolution in \eqref{sp:transformed-pde} maps
bounded functions to Lipschitz functions with a constant uniform in
the starting modulus $p\ge p_0$.
\end{lemma}
\begin{proof}
We first justify using the diffusion all the way to the chamber
boundary. The drift in one tuple is
$\frac14(\sum_{j\ne i}\cot((w_i-w_j)/2))_{i=1}^4$.
On the lifted convex chamber, use $-\log m$, shifted to be nonnegative,
as a Lyapunov function. If $\alpha=4/3$ is the density exponent, the
cotangent identity shows that its generator has a singular contribution
proportional to $(\alpha-\alpha^2)\sum_{i1$.
\end{proof}
Let $W_-=e^{\lambda p}(T^+-T^-)/h$, and define
\[
(\Pi F)(x,y)=\frac1{2\pi}\int_0^{2\pi}
F(x,y+\phi\mathbf1)\,d\phi
\]
on simultaneous-rotation-invariant functions. Equivalently, $\Pi$
is projection to center frequencies $(0,0)$. A one-step cyclic
relabeling switches $T^+$ and $T^-$, while $h$ is unchanged.
Thus $W_-$ has exactly the symmetries of Lemma~\ref{sp:gaps}.
\begin{proposition}[Uniform transmission asymptotics]
\label{sp:transmission-asymptotics}
There are constants $K\ge0$, $\sigma>0$, and $C<\infty$ such that,
uniformly over the open angle chamber and all sufficiently large $p$,
\begin{align}
\|W_-(p)\|_\infty&\le Ce^{-3p/4},
&\|\Pi W_-(p)\|_\infty&\le C(1+p)e^{-p},
\label{sp:odd-decay}\\
T^\pm(p,x,y)&=e^{-\lambda p}
\bigl(Kh(x,y)+O(e^{-\sigma p})\bigr).
\label{sp:rank-one-round}
\end{align}
Moreover,
\begin{equation}\label{sp:odd-regularity}
\operatorname{Lip}(W_-(p))\le Ce^{-3p/4},\qquad
\|W_-(p+\ell)-W_-(p)\|_\infty
\le Ce^{-3p/4}\sqrt\ell\quad(0\le\ell\le1).
\end{equation}
The function $h$ is uniformly $1/3$-H\"older on the closed chamber.
\end{proposition}
\begin{proof}
For any transformed solution put
$F_p=B_p\cdot\nabla W(p)+V_pW(p)$.
Lemma~\ref{sp:smoothing} implies $\|F_p\|_\infty\le Ce^{-p}$
once $p$ is sufficiently large. Variation of constants gives
\begin{equation}\label{sp:duhamel}
W(p)=P_{p-p_1}W(p_1)+\int_{p_1}^pP_{p-s}F_s\,ds.
\end{equation}
This identity also follows directly by It\^o's formula with $D$,
first stopping on inner exhaustions: on the interval in question
the solution and the forcing are bounded, and collisions are not hit.
For $W_-$ the forcing respects simultaneous rotation invariance and
the two cyclic sign changes. Apply the $3/4$ gap to
\eqref{sp:duhamel}, and then apply the unit-time $L^2$-to-supremum
smoothing to all semigroup times at least one. For shorter times
use the supremum bound on $F_s$. The convolution with $e^{-s}$ is
$O(e^{-3p/4})$. After projecting by $\Pi$, which commutes with $D$,
the gap is $1$ and the convolution is $O((1+p)e^{-p})$.
This proves \eqref{sp:odd-decay}. It does not require $B_p$ to
commute with independent rotations: the projected forcing is
estimated after projection.
For either $W^+$ or $W^-$ separately, $D$ has a positive gap off
constants. Indeed the center gap is $3/32$ and the relative gap is
at least $1/2$. The same argument shows exponential convergence of
$W-\int W\,d\mu$ to zero. Also
$\partial_p\int W\,d\mu=\int F_p\,d\mu=O(e^{-p})$, so its mean
converges exponentially. The first estimate of
\eqref{sp:odd-decay} makes the two limiting constants equal; call
their common value $K$. Multiplication by $e^{-\lambda p}h$
proves \eqref{sp:rank-one-round}.
The unit-interval Lipschitz estimate in Lemma~\ref{sp:smoothing},
applied to the homogeneous perturbed evolution for $W_-$, improves
its Lipschitz bound to $Ce^{-3p/4}$. To obtain time regularity,
the same diffusion has expected angle displacement at most
$C\sqrt\ell$ in time $\ell\le1$, uniformly in its initial point.
Here is a bound that remains valid near a collision. Apply It\^o's
formula to squared distance from the initial lift. Each pair in
the scalar product with the singular drift contributes a constant
multiple of
\[
(v-v_0)\cot(v/2),\qquad v,v_0\in(0,2\pi),
\]
which is bounded above uniformly: use $v-v_0\le v$ for $v\le\pi$
and $v-v_0\ge v-2\pi$ for $v\ge\pi$.
The bounded additional drift and the Brownian quadratic variation
then give $\E|Z_\ell-Z_0|^2\le C\ell$, by localization and
Gronwall's inequality. The Feynman--Kac representation over time
$\ell$, the spatial Lipschitz bound, and the bounded potential give
the time estimate in \eqref{sp:odd-regularity}.
Finally $J$ is a bounded Lipschitz nonnegative function on the closed
chamber, and taking a cube root is $1/3$-H\"older. The assertion
for $h$ follows by taking products.
\end{proof}
==== END A-Pivotal-Amplitude-for-Voronoi-Percolation-from-Cardys-Formula//03-spectrum.tex ====
==== BEGIN A-Pivotal-Amplitude-for-Voronoi-Percolation-from-Cardys-Formula//04-shape.tex ====
\section{Separating the conformal data of the two ends}
\label{sh:section}
\label{sec:shape}
The estimates of Section~\ref{sp:section} are expressed in the
uniformizing coordinates of the entire annulus. To use them in a
transfer operator, their leading term must instead depend separately
on the inner and outer explored regions. We prove the requisite
comparison uniformly over their shapes. Only separation of the
two ends is needed; no boundary smoothness bound is imposed.
Let $K_i$ be a closed Jordan region containing $0$ in its interior,
and let $U_o$ be a bounded Jordan domain containing $K_i$.
The annulus under consideration is $U_o\setminus K_i$.
Fix constants $c_*,C_*>0$ and assume that
\begin{equation}\label{sh:shape-hypotheses}
K_i\subset\{|z|\le a\},\quad
\operatorname{diam}K_i\ge c_*a,\qquad
\{|z|1\},
\qquad w_i(z)=z/l_i+O(1)\quad(z\to\infty),
\]
with $l_i>0$, and let
\[
w_o:U_o\longrightarrow\{|w|<1\},\qquad
w_o(0)=0,\quad w_o'(0)=1/l_o>0.
\]
Thus $l_i$ is the logarithmic capacity of $K_i$ and $l_o$ is the
conformal radius of $U_o$ at $0$. Write $y^0,x^0$ for the angles of
the inner and outer marks in these maps. Capacity-diameter bounds
for continua and the Koebe estimates imply
\begin{equation}\label{sh:end-scales}
l_i\asymp a,\qquad l_o\asymp b,
\end{equation}
with constants depending only on $c_*,C_*$.
\begin{lemma}[Uniform end-map comparison]\label{sh:comparison}
Let $(p,x,y)$ be the modulus and marked angles in a uniformization
of $U_o\setminus K_i$, with angular direction the same on both
boundary components. Put $p'=\log(l_o/l_i)$. The common rotational
normalization of the annulus map can be chosen so that
\begin{equation}\label{sh:comparison-estimate}
|p-p'|\le C\frac ab,\qquad
|x-x^0|+|y-y^0|
\le C\bigl(1+\log(b/a)\bigr)\frac ab.
\end{equation}
Distances in the second inequality use compatible cyclic lifts.
The constant is uniform over all Jordan boundaries satisfying
\eqref{sh:shape-hypotheses}, including all placements of the marks.
\end{lemma}
\begin{proof}
Define the single-valued analytic corrections
\[
g_i(z)=\log\frac{l_iw_i(z)}z,
\qquad g_o(z)=\log\frac{l_ow_o(z)}z,
\]
with branches vanishing at infinity and at zero, respectively.
The quotient defining $g_o$ has no zeros in $U_o$ and the apparent
singularity at zero is removable; the exterior quotient has zero
winding and its logarithm is normalized at infinity.
Univalent distortion and \eqref{sh:end-scales} give
\begin{equation}\label{sh:correction-bounds}
|g_o(z)|\le Ca/b\quad (|z|\le C_1a),\qquad
|g_i(z)|\le Ca/b\quad (|z|\ge c_1b),
\end{equation}
for every fixed $C_1<\infty$ and $c_1>0$, once $a/b$ is small
enough. The relevant sets in these inequalities are contained in
the respective map domains. The same bounds hold in fixed round
collars in the single-end coordinates. If $\psi_i=w_i^{-1}$,
the maximum principle applied to $\psi_i(w)/w$ gives
$|\psi_i(w)|\le a|w|$ for $|w|>1$.
For $\psi_o=w_o^{-1}$, Koebe's distortion bound gives
$|\psi_o(w)|\ge l_o|w|/(1+|w|)^2$.
Thus the inverse exterior map sends $1\le|w_i|\le2$ into
$|z|\le2a$, and the inverse interior map sends, for example,
$1/2\le|w_o|<1$ into $|z|\ge cb$.
These observations are the reason arbitrary roughness of the physical
boundaries does not change the constants.
Consider the multivalued analytic function
\[
H(z)=\log(z/l_i)+g_i(z)+g_o(z).
\]
It has period $2\pi i$, and its real part is within $Ca/b$ of $0$
on the inner boundary and of $p'$ on the outer boundary. Let
$A(z)$ be an annulus logarithm, normalized by
$0<\operatorname{Re}A0$ and $C<\infty$,
depending only on the fixed constants in
\eqref{sh:shape-hypotheses}, such that the transmission probabilities
of every such marked annulus satisfy
\begin{equation}\label{sh:rank-one}
\left|T^\pm-
K\,l_i^\lambda J(y^0)^{1/3}\,
l_o^{-\lambda}J(x^0)^{1/3}\right|
\le C(a/b)^{\lambda+\sigma_1}.
\end{equation}
Here $K$ is the common constant in
Proposition~\ref{sp:transmission-asymptotics}. If one rotates the
inner end, with its marks and prescribed colors, through angle $\phi$
about $0$ while keeping the outer end fixed, then
\begin{equation}\label{sh:rotation-average}
\left|\frac1{2\pi}\int_0^{2\pi}
\bigl(T^+_\phi-T^-_\phi\bigr)\,d\phi\right|
\le C(a/b)^{2+\sigma_2}.
\end{equation}
The same conclusion holds if the outer end is rotated instead.
Both estimates remain uniform for Jordan approximants to the
prime-end boundaries of Section~\ref{sec:annuli}, provided they
satisfy \eqref{sh:shape-hypotheses} with the same fixed constants.
\end{proposition}
\begin{proof}
Write $\rho=a/b$ and $q=\log(1/\rho)$. By
\eqref{sh:end-scales}, $p'=q+O(1)$. Set
$\eta=C(1+q)\rho$, the angular error in
Lemma~\ref{sh:comparison}. The $1/3$-H\"older bound for $h$
and the first inequality of that lemma give
\[
|e^{-\lambda p}h(x,y)-e^{-\lambda p'}h(x^0,y^0)|
\le C\rho^\lambda(\rho+\eta^{1/3}).
\]
Combining this with \eqref{sp:rank-one-round} proves
\eqref{sh:rank-one}; for example any
$0<\sigma_1<\min\{\sigma,1/3\}$ is sufficient after changing
the constant. Since
$e^{-\lambda p'}=(l_i/l_o)^\lambda$, the leading term has exactly
the displayed separated form.
For the signed estimate put $U=T^+-T^-=e^{-\lambda p}hW_-$.
Equations~\eqref{sp:odd-decay} and
\eqref{sp:odd-regularity}, together with the H\"older bound for
$h$, show that replacing the actual annular data by the two
single-end data costs at most
\begin{equation}\label{sh:signed-shape-error}
C\rho^2\bigl(\rho^{1/2}+\eta+\eta^{1/3}\bigr).
\end{equation}
This bound is uniform over the rotation of either physical end.
In particular it is a power improvement on $\rho^2$.
The capacity $l_i$ is unchanged by rotation of the inner end, and
its normalized map is
$w_{i,\phi}(z)=e^{i\phi}w_i(e^{-i\phi}z)$.
Consequently its marked single-end angles are exactly
$y^0+\phi\mathbf1$. The factor $h$ is unchanged by rotating
either tuple separately. Thus the rotation average in the unperturbed
data is
\[
e^{-\lambda p'}h(x^0,y^0)
(\Pi W_-)(p',x^0,y^0),
\]
whose absolute value is at most
$C(1+q)\rho^{\lambda+1}=C(1+q)\rho^{9/4}$ by
\eqref{sp:odd-decay}. Add the uniform error
\eqref{sh:signed-shape-error}.
Any $0<\sigma_2<1/4$ is then admissible, after increasing the
constant and restricting to sufficiently small $\rho$.
Rotating the outer end gives the same projection, by simultaneous
rotation invariance.
Every estimate was obtained with constants depending only on the
separation and scale conditions, not on boundary smoothness or mark
separation. It can therefore be applied directly to the continuum
function $T$ evaluated on the conformal data of the Jordan cycles
approximating an explored domain. Under admissible convergence,
Proposition~\ref{an:limit} separately identifies the limit of the
discrete transmission probabilities with that continuum function; no
reflection across a physically nonsimple limiting bank is being
asserted.
\end{proof}
==== END A-Pivotal-Amplitude-for-Voronoi-Percolation-from-Cardys-Formula//04-shape.tex ====
==== BEGIN A-Pivotal-Amplitude-for-Voronoi-Percolation-from-Cardys-Formula//05-transfer.tex ====
\section{Uniform transfer of signed connection states}
\label{tr:section}
\label{sec:transfer}
The estimates of the preceding section concern annuli with four prescribed
switches at each end. A discrete crossing test, however, can present an
arbitrarily complicated connection state to an annulus. Moreover, the
outside of that annulus need not have a scaling limit. We now prove
operator estimates that are uniform over these states and outside data.
The important distinction is between the two annular ends, where arbitrary
data are allowed, and an independent region between them, where the
scaling-limit arguments take place.
Throughout this section the Poisson intensity is one, the center of all
circles is fixed, and $\lambda=5/4$. We use the localization and mesh-first
arm estimates recalled above from \cite[Sections~2--3]{V}. The constants
implicit in choices of collars and buffers are fixed once and for all.
\subsection{Cuts, connection states, and transfer operators}
Fix a sufficiently small constant $\eta>0$. A \emph{seam at radius $r$}
consists of the marked Poisson process in the collar
\[
(1-\eta)r<|z|<(1+\eta)r,
\]
together with auxiliary randomness used to select a graph cycle. A
local occupancy test, denoted $G_r$, ensures that the graph and the vertex
stars through a narrower collar are determined by these variables and
that their diameters are smaller than a fixed small fraction of $\eta r$.
We choose the test and the narrower collar with buffers at both ends, so
that
\begin{equation}
\Pp(G_r^c)\le C e^{-cr^2}.
\label{tr:screen}
\end{equation}
On $G_r$ choose a simple site cycle $\Gamma_r$ surrounding the center,
inside the narrower collar. The choice uses the geometry but not the
colors. The test and the choice are rotation equivariant; an independent
uniform angular axis may be included among the seam variables to break
ties.
For completeness, such a screen can be obtained by requiring that every
point in a closed intermediate collar be within a sufficiently small
distance, proportional to $r$, of a nucleus in the larger collar. This
covering-distance condition is rotation invariant and has the
exponential failure bound in \eqref{tr:screen}. Following a circle in the
site triangulation and deleting loops gives the required cycle. Buffers
and the same covering condition determine all its vertex stars. A
nucleus beyond either extremity of the collar cannot affect the graph
on the other side: its cell would have to pass through the screened
intermediate collar, where all cells are small. Consequently the graph
on each side of $\Gamma_r$, including its attachments to the cycle, can
be read from the seam and the Poisson variables on that side. Conditional
on the seam, the variables used on the two sides are independent.
The colors on $\Gamma_r$ determine an even number of switches. An inside
connection state is a noncrossing pairing of those switches by interface
strands in the disk on the inside. The pairing, together with the
monochromatic runs on the cycle, determines all boundary connectivity.
Closed interface loops carry no information and are not stored. We
allow every formal noncrossing pairing as a state, whether or not it is
realized by a particular inside graph. Such pairings respect the
alternating color convention: the endpoints of each pair have opposite
parity in cyclic order. Gluing a pairing to the annular strands is
therefore defined without a realizability restriction.
Write $\Sigma_r$ for the seam variables and $\mathcal S_r(\Sigma_r)$ for
this finite state set on $G_r$. A \emph{message} is a measurable field
of signed measures $v_{\Sigma_r}$ on $\mathcal S_r(\Sigma_r)$ such that
\[
v_{\Sigma_r}(\mathcal S_r(\Sigma_r))=0,
\qquad v_{\Sigma_r}=0\ \hbox{on }G_r^c.
\]
Its norm is
\begin{equation}
\|v\|_r
=\operatorname*{ess\,sup}_{\Sigma_r}
\|v_{\Sigma_r}\|_{\TV}.
\label{tr:message-norm}
\end{equation}
Here total variation is the sum of the absolute point masses, so that a
difference of probability measures has norm at most two. Finite state
sets can be numbered measurably; the bounded fields of zero-mass measures,
modulo seam-law null sets, form a Banach space $\mathcal B_r$.
If the collars at radii $r0$ and $C<\infty$ with the following property. For every
sufficiently large integer $n$, set $L=2^n$. There is a threshold $r_0(L)$
such that, for $r\ge r_0(L)$, the transfer $M=M_{r,Lr}$ satisfies
\begin{align}
\|M\|&\le C L^{-\lambda}, \label{tr:block-size}\\
M&=M_1+E,\qquad \operatorname{rank}M_1\le1,
\qquad \|E\|\le C L^{-\lambda-\delta},
\label{tr:block-rank}\\
\|M|_{\mathcal B_r^{\mathrm{even,iso}}}\|
&\le C L^{-2-\delta}.
\label{tr:block-cancellation}
\end{align}
The constants $C,\delta$ do not depend on $L$ or $r$. Every norm in the
conclusion includes the essential supremum over successful output
seams, including their colors. The rank-one operator may depend on
$r$ and $L$.
\end{proposition}
The reduction has a simple mechanism. Six surviving interfaces already
cost a power strictly greater than two, while four interfaces leave just
one signed connection coordinate. We isolate an independent region in
which to obtain four-tip boundaries, verify their convergence, and then
apply the separated-end estimates to that coordinate. Summing over the
first four-tip scales gives both the rank-one approximation and the
color--rotation cancellation.
\subsection{An independent region for the limiting argument}
Fix $L$ for the moment and rescale by $r$. Thus the mesh tends to zero
as $r\to\infty$, whereas all radii used in the present argument lie in a
fixed finite range. Choose auxiliary starting cycles near radii $8r$
and $Lr/8$. Their geometry is determined in small collars separated
from both original seams. From either starting cycle we shall explore
towards the middle of the annulus, stopping at one of finitely many
\emph{barriers}: color-independent site cycles approximating specified
concentric circles in curve order. Their colors remain unread until
the exploration proceeds past them. A \emph{stopping circle} means the
limiting circle of the current barrier. All cycles may be
made chord free on the side approached by the exploration.
We impose auxiliary occupancy tests in this intervening region. Unlike
the actual seam tests, these may require a relative mesh tending to
zero: use covering distances that tend slowly to zero in rescaled
coordinates. For the fixed finite collection of collars under
consideration, their total failure probability is $o(1)$. Their supports
are separated from the input and output seams. On success, geometry
around the two starting cycles and throughout the region between them
agrees with the geometry of a full-plane Poisson sample, obtained by
adjoining independent variables outside that region. In particular,
all these $o(1)$ failure bounds hold uniformly conditional on either or
both original seam variables.
There is also a local version of this construction. An end experiment
stopped at a barrier uses only variables from a buffer just before its
starting cycle through a small fixed-factor enlargement past that
barrier, together with the variables between its starting cycle and its
own seam. Its localization tests stop at that enlargement. If two
barriers are separated by a sufficiently large fixed factor, the
supports for the two end experiments are disjoint. Extra tests across
the middle can then be added when evaluating an actual annular
transmission. Deleting those extra tests from an integral with bounded
weights changes it by $o(1)$, uniformly in the original seams. It is
only after this deletion that the two end integrals are factored.
Figure~\ref{tr:figure} records the radial order and the gaps between
the supports of the two end experiments.
\begin{figure}[tb]
\centering
\begin{tikzpicture}[x=0.88cm,y=0.75cm,>=Latex,font=\small]
\fill[black!12] (0,-0.26) rectangle (0.42,0.26);
\fill[black!12] (11.58,-0.26) rectangle (12,0.26);
\fill[black!5] (1.55,-0.18) rectangle (4.05,0.18);
\fill[black!5] (7.95,-0.18) rectangle (10.45,0.18);
\draw[thick] (0,0)--(12,0);
\foreach \x in {0.2,2,3.7,8.3,10,11.8}
\draw (\x,-0.14)--(\x,0.14);
\node[align=center,below] at (0.2,-0.42) {input\\seam};
\node[align=center,below] at (2,-0.42) {inner start\\$8r$};
\node[align=center,below] at (3.7,-0.42) {barrier\\$a$};
\node[align=center,below] at (8.3,-0.42) {barrier\\$b$};
\node[align=center,below] at (10,-0.42) {outer start\\$Lr/8$};
\node[align=center,below] at (11.8,-0.42) {output\\seam};
\draw[->,thick] (2,0.65)--(3.7,0.65);
\draw[->,thick] (10,0.65)--(8.3,0.65);
\node[align=center] at (6,0.72) {unexplored annulus};
\draw[<->] (1.2,1.5)--(10.8,1.5);
\node[fill=white,inner sep=3pt] at (6,1.5) {independent Poisson region};
\end{tikzpicture}
\caption{The radial order of two end experiments with separated barriers,
on a schematic logarithmic scale. Explorations start inside the transfer
block, independently of its two seams. Each shaded end support extends
a little beyond its last barrier; the gap between those supports permits
their independent integration. The original seam screens remain
imposed throughout.}
\label{tr:figure}
\end{figure}
The following elementary observation is the uniformity mechanism used
below. Its purpose is to avoid any assertion of a uniform scaling
limit conditional on an atypical explored shape.
\begin{lemma}[Domination before conditioning on end shapes]
\label{tr:domination}
Suppose a contribution to $M_{r,Lr}v$ is expressed, after exploring from
the auxiliary starting cycles, as an integral of an inner scalar
coefficient, a bounded middle test, and an outer signed state measure.
If the middle test is replaced with absolute error $F\ge0$, where $F$
depends only on the independent region just described, then the error
in output norm is at most
\begin{equation}
C\|v\|_r\,\E_{\mathrm{core}}F+o(1)\|v\|_r.
\label{tr:domination-bound}
\end{equation}
The same bound applies to discarding an event there, by taking $F$ to
be its indicator. The expectation is under the unweighted full-plane
comparison law; the bound is uniform over successful output seams.
\end{lemma}
\begin{proof}
For a fixed realization, pushing $v_{\Sigma_r}$ to any intermediate
state set contracts total variation. When that set has two states, its
zero-mass image has the form $\alpha(\delta_B-\delta_W)$, with
$|\alpha|\le\|v\|_r$. Pushing the two-state difference through the other
end gives a signed measure $q$ with $\|q\|_{\TV}\le2$. Hence the
pointwise norm of the replacement error is bounded by
$2\|v\|_rF$. The same argument, summing absolute masses before a
two-state reduction, handles discarded events. No regularity of the
dependence of $\alpha$ or $q$ on the seam data is needed.
On the auxiliary localization successes, $F$ is a function of marked
Poisson variables independent of both original seams and has the stated
full-plane comparison law. Integrate the pointwise bound conditional
on the output seam. Auxiliary failures contribute the final $o(1)$
term, also uniformly, because their supports are off the original seams.
The seam success indicators themselves are not deleted.
\end{proof}
\subsection{Exploration up to the first four-tip frontier}
First push the input message from its original seam to the inner
auxiliary starting cycle, using the marked variables in the intervening
attachment region. The subsequent exploration uses the colored
starting cycle and the variables towards its barrier; it never consults
an attached cap state. Dependence on the input message stays in the
pushed signed coefficients. At the outer end the corresponding
attachment operation pushes states from its auxiliary cycle towards
the original output seam.
At the inner auxiliary cycle, reveal its colors and trace every switch
into the annulus. A wall is followed until it pairs with another traced
wall or until its next color query would read a vertex on the current
barrier. In the second case, stop before that query. The stopped wall
ends at a switch edge whose next triangle has its opposite vertex on
the barrier. No barrier colors have been read. The analogous outer
experiment is directed inwards. Increasing the inner barrier radius
by a factor two, or decreasing the outer barrier radius by a factor
two, continues the same wall system. Tracing all walls in a previously
colored sample shows that the outcome does not depend on their tracing
order.
We call the unpaired stopped wall ends the \emph{surviving tips}.
Their number is even and decreases as the barrier is advanced. The
first barrier with at most four surviving tips will be the end's
reduction barrier. A reduction to zero or two tips kills every
zero-mass message. A reduction to exactly four leaves precisely two
cap states. We next verify both this assertion and the geometric
properties needed for the annular transmission limit.
\begin{lemma}[Frontier and arm counts]
\label{tr:frontier}
For either end experiment, outside an event whose probability tends to
zero as the permitted separation of tips tends to zero, mesh first,
the tips at each of finitely many fixed-scale barriers have distinct
limiting positions. The boundary facing the unqueried barrier is a
simple site cycle whose switches are exactly these tips. In particular:
\begin{enumerate}
\item If there are zero or two tips, the induced map on zero-mass
connection-state measures is zero.
\item If there are at least six tips, six disjoint bulk arms cross the
region from the starting cycle to the barrier, after fixed-factor
crops at the two ends.
\end{enumerate}
All probabilistic assertions are made under the unweighted exploration
law, before conditioning on a particular history.
\end{lemma}
\begin{proof}
First consider two tips approaching the same point of the barrier.
Use a graph disk patch with its base on the barrier and a half-annulus
on the exploration side. Extend each stopped wall through its last
triangle to the base, only for this geometric argument; no barrier
color is queried. The two wall fingers give two proper traversals of
the half-annulus, with fixed margins at its two semicircular ends.
Following the sites on their banks gives three disjoint free arms in
the sectors on the two exterior sides and between the fingers. These
sites are on the exploration side, not on the barrier. Short spokes
through successive wall triangles keep each bank in its sector. The
base through the tips prevents an exterior bank from escaping around
a finger's end. Cropping the last mesh steps gives the same count
when two stopping triangles share a barrier vertex.
This is the free-bank-shadow count for two traversals in the boundary
argument of \cite[Section~3]{V}. The local boundary three-arm exponent
is strictly greater than one. Covering the barrier by $O(s^{-1})$
patches of radius $s$ therefore excludes colliding tips as $s\downarrow0$,
mesh first. The BK inequality applied to the free shadows also makes
the number of fixed-scale traversals tight.
For the frontier assertion, fill the starting side of the starting
cycle with a disk, using the sphere for the outside experiment.
Attach the queried triangles along the explored bands and add all
edges between revealed vertices. The resulting graph is
two-connected: attaching a triangle along an existing edge preserves
two-connectivity, as does adding an edge between existing vertices.
Thus the boundary of its face containing the unqueried barrier is a
simple cycle. The barrier and its paths towards the unexplored middle
remain in that face. In particular each stopping triangle is incident
with this same face on its unread side.
There is a useful invariant: every revealed vertex has a revealed path
of its own color to the starting cycle. It holds initially, and a newly
queried triangle vertex has the color of one endpoint of the incoming
heterochromatic edge, extending such a path. Thus an added
heterochromatic edge between revealed vertices cannot belong to an
unstarted wall. Such a wall would either close in the annulus or return
to the barrier without visiting the starting cycle; in either case it
would separate one bank from that cycle, contradicting its revealed
same-color path. Every heterochromatic revealed-vertex edge therefore
belongs to the traced wall system.
To identify the colors along the frontier, extend the stopped walls
to the barrier as above. These proper arcs, together with the walls
that paired back to the starting cycle, divide the explored collar
into regions with their consistent bank colors. Every revealed vertex
is either a starting-cycle vertex or was queried in a wall triangle.
Its color agrees with the relevant bank. An added edge cannot cross
one of these wall arcs, and the preceding invariant excludes any
untraced switch there. Previously crossed switch edges have triangles on
both sides in the revealed bands. The only switches exposed to the
remaining face are consequently the surviving stopping edges.
With zero or two switches there is just one noncrossing cap pairing.
Every input state gives that same pairing, so a zero-mass difference
vanishes. With six or more surviving wall fingers, their bank shadows
give six disjoint site arms in successive sectors between the starting
cycle and the barrier. Fixed-factor crops remove the two ends, where
different shadows could otherwise meet. The arbitrary-color six-arm
bound is applicable, so no particular numbering or color order of the
six arms is required.
\end{proof}
The next lemma verifies the non-Jordan boundary issue rather than
presuming that scalar Cardy convergence applies to a random annulus.
\begin{lemma}[Admissibility of four-tip frontiers]
\label{tr:admissible}
At a fixed barrier, restrict the unweighted exploration law to the event
of exactly four surviving tips. Along subsequences with good geometry
as in \cite[Section~2]{V}, the four monochromatic frontier arcs are tight
in curve order. In every coupled subsequential limit, after constant
pauses are erased, each arc is simple and meets the stopping circle
only at its two prescribed endpoints. The four endpoints are distinct.
For two such experiments ending at well-separated barriers, their
residual annulus satisfies the admissibility conditions of
Proposition~\ref{an:limit}. If $t_r$ is the discrete
through-transmission probability conditional on the complete geometry
and the two end histories, and $T_r$
is the continuum transmission function evaluated on its actual
conformal data, then, for fixed $L$ and the fixed finite list of barriers,
\begin{equation}
\E_{\mathrm{core}}\!\left[
\boldsymbol 1_{\{\text{four tips at both ends}\}}
|t_r-T_r|\right]=o(1).
\label{tr:mean-limit}
\end{equation}
The expectation concerns unweighted histories, not a uniform conditional
estimate for all possible histories.
\end{lemma}
\begin{proof}
The BK and successive-excursion argument gives tightness of the four
frontier arcs. Indeed repeated annular traversals provide disjoint
free arms; all sites used, including those on the auxiliary starting
cycle, have their original fair colors. This is applied first at
fixed radii and then at successively smaller excursion scales.
The contact arguments below are the face-boundary arguments in
\cite[Section~3]{V}; we give the details relevant to the present
frontier.
Every frontier vertex off the starting cycle belongs to a revealed
wall band. On its revealed side it has an opposite-colored neighbor
with a bank path back to the starting cycle. Consequently a visit of
a frontier arc to the stopping circle other than at its designated
endpoint, with a positive excursion on both sides of the visit, gives
three free arms in a half-patch: two along the arc and one along the
opposite bank. The same argument excludes an intermediate return to
an endpoint. The boundary three-arm exponent and a covering of the
circle exclude all such visits. A nonconstant interval contained in
the circle is excluded by the one-arm bound at a countable dense set
of circle points. Constant pauses can be removed from the
parametrization. Distinctness of the four tips follows from
Lemma~\ref{tr:frontier}.
Consider next a self-return of one monochromatic frontier arc at a
point away from the starting and stopping circles. Separate the two
visits by a fixed positive excursion scale. In a smaller annulus
around the proposed contact, the arc supplies four proper traversals.
Its opposite bank paths lie on the revealed side of the frontier
cycle. They may all be joined through the starting cycle when making
the planar separation argument. This joining set need not be
monochromatic at the starting cycle: the working annulus misses that
cycle, and within the working annulus every part of the joining set
is genuinely of the opposite color.
At least two complementary sectors have a frontier traversal on their
boundary whose revealed side faces the sector. Each such sector
contains an opposite-colored longitudinal crossing. To verify this assertion,
choose transverse cuts at intermediate scales with margins, leaving
both ends of that frontier traversal beyond the cuts. If the joined
neighbor set did not cross the sector longitudinally, planar duality
would provide a transverse crosscut avoiding it. Start this crosscut
from that frontier traversal and stop at its first subsequent hit of the
frontier cycle. In the disk on the revealed side, the two traversal ends
and the two crosscut ends alternate along the frontier. The crosscut
therefore separates their neighbor spokes, contradicting the joined
neighbor set, which lies on the revealed side and avoids the
crosscut.
The argument remains valid when the traversals backtrack. Choose the
transverse cuts along intermediate graph cycles, or apply Hex duality
with such a cycle temporarily wired in the sector. Two disjoint cuts
bound a quadrilateral whose side arcs belong to the chosen traversals
and whose interior avoids those whole proper traversals, not merely
the selected side subarcs. Thus the crosscut's first subsequent
frontier hit lies outside the whole traversal from which it started,
so the alternating boundary order used above persists under
backtracking. The crosscut is in the quadrilateral's interior, whereas the end spokes are beyond
the cuts. They thus avoid the crosscut even if other portions of the
frontier enter the sector. Cropping the margins leaves two disjoint
opposite-colored arms in different sectors, in addition to the four
arms along the monochromatic arc. This gives six disjoint bulk arms.
The bulk exponent strictly greater than two excludes these contacts
by a covering argument. At a self-contact on the starting circle,
the four arc traversals alone suffice: the arbitrary-color four-arm
exponent is strictly greater than one, and the possible contact
locations lie on a fixed circle.
All these exclusions are made for distinct visits with fixed positive
excursion scales before those scales decrease. Countably many scales
and finite ball coverings make the assertions simultaneous. They
bound joint probabilities with the four-tip event; no division by the
probability of a rare history is involved.
We now identify the remaining domain; see
Figure~\ref{fig:frontier-lobes}. Cut along the barrier, using the
four short incidences from the tip edges through their terminal
triangles. Between consecutive tips, the frontier arc and its
corresponding barrier interval bound a lobe polygon. The four lobes
are attached over open intervals to the untouched region on the middle
side of the barrier. Each lobe converges in order to a Jordan lobe,
because its frontier arc is simple and meets the barrier only at its
endpoints. Different lobe boundaries may touch in physical projection;
their interiors remain disjoint, and their distinct accesses are
retained. With two well-separated barriers there is a fixed open
annular region between the ends.
We verify that adjoining the lobes still gives an annulus, even when
their boundaries touch. On either side of this open annular region,
start with the closed disk bounded by the corresponding stopping circle,
using the sphere for the outer side. The complementary set on that
side is obtained by removing the lobe interiors and their open
attachment intervals. Each lobe's free frontier arc remains in this
complement: it cannot enter another lobe's interior, since their Jordan
interiors are disjoint, and it meets the stopping circle only at its
own endpoints, never on another open attachment. Connect a point of
the remaining closed set to the preserved starting-side region by a
path in the closed disk, with its interior off the stopping circle.
Whenever the path enters a lobe, replace the portion from its first
entry to its last exit by the intervening subarc of that lobe's free
frontier. The entry and exit lie on this free arc. The replacement
avoids every lobe interior and every open attachment, so it cannot
undo previous replacements. There are only four lobes; after finitely
many replacements the path is wholly in the complementary set.
Thus each side has a connected complement. The two such nondegenerate
continua are separated by the open annular region and exhaust the
complement of the residual domain. The domain is therefore doubly
connected, with its two boundary components physically apart.
Lemma~\ref{an:back-lobes} now gives uniform convergence
of the closed-annulus parametrizations with their prime-end order.
The boundary traversal consists of finitely many individually simple
arcs. These are exactly the hypotheses required by
Proposition~\ref{an:limit}.
Finally extract, from any sequence of scales, a further sequence on
which the localized full-plane geometries are good in the sense of
\cite[Section~2]{V}. Conditional on those geometries, couple convergent
subsequences of the frontier histories just described. All unqueried
colors in the residual face remain independent and fair. Apply
Proposition~\ref{an:limit} path by path to the converging graph annuli.
The continuum function on the actual approximating conformal data
also converges, by its continuity. Bounded convergence proves
\eqref{tr:mean-limit} along the further sequence and hence along the
original sequence. Unused colors on the removed sides of the
frontiers may be revealed or integrated in their own end variables;
they do not affect this argument.
\end{proof}
\input{figures/lobes}
The probabilistic conclusions of the last two lemmas all concern the
independent region. Lemma~\ref{tr:domination} therefore makes their
discarded probabilities and the error in \eqref{tr:mean-limit} uniform
for the operator norm, even when a message depends arbitrarily on the
seam and on its attachment information. This is the reason the
explorations start at auxiliary cycles rather than at the original
seams.
\subsection{The first-reduction decomposition}
Index the inner barriers by radii
\[
a_j=8\cdot2^j r,
\qquad j=1,2,\ldots,
\]
and the outer barriers by
\[
b_k=2^{-k}Lr/8,
\qquad k=1,2,\ldots.
\]
Each list is finite, ending before the opposite starting region. Fix
a large integer $d$ so that
\begin{equation}
j+k\le n-d
\label{tr:used-pairs}
\end{equation}
ensures disjoint buffered end supports and sufficient separation for
Proposition~\ref{sh:separated-ends}. A \emph{used pair} is a pair
satisfying \eqref{tr:used-pairs} at which the two experiments first
reduce to exactly four tips. A first reduction to fewer than four
contributes zero by Lemma~\ref{tr:frontier}.
Choose $\tau>0$ smaller than the excess of the mesh-first six-arm
exponent over two. Let $\rho_j^{\rm in}$ and $\rho_k^{\rm out}$ be the
subprobability laws of the corresponding first four-tip histories,
including local screens and the variables attaching each history to its
original seam. The inner law integrates the input seam. All outer
laws and outer integrals below are conditional on the fixed output seam
$\Sigma_{Lr}$; in particular they define fields over that seam, not
averages of it. The dependence on seam variables in the
attachments will be kept in the scalar and signed measure factors
below, rather than in any assertion about typical shapes. We first
bound the masses of these unweighted history laws; pointwise bounded
message factors will then preserve the bounds up to constants.
\begin{lemma}[First-reduction tails]
\label{tr:tails}
For fixed $L$, the end-history subprobability masses satisfy, in the
mesh-first limit,
\begin{equation}
\|\rho_j^{\rm in}\|_{\TV}
\operatorname*{ess\,sup}_{\Sigma_{Lr}}
\|\rho_k^{\rm out}(\cdot\mid\Sigma_{Lr})\|_{\TV}
\le C 2^{-(2+\tau)j}2^{-(2+\tau)k}+o(1)
\label{tr:history-weight}
\end{equation}
for each used pair $(j,k)$. Consequently, after inserting arbitrary
middle tests of modulus at most one, the same bound up to a constant holds
for the corresponding operator contribution on inputs of norm at most
one. The part of the transfer not represented
by used pairs has norm at most
\begin{equation}
C(n+1)^2L^{-2-\tau}+o(1).
\label{tr:unused}
\end{equation}
Both estimates are uniform for input messages of norm at most one and
for successful output seams.
\end{lemma}
\begin{proof}
Before the first reduction at level $j$, there are at least six tips
at the preceding level. Lemma~\ref{tr:frontier} then requires six arms
from the starting region to that level. The mesh-first six-arm bound
gives $C2^{-(2+\tau)j}$, with a changed constant for the first few
levels. The same statement holds at the outer end, uniformly in its
original seam: the necessary six-arm event is read in the independent
region, while attachment variables and success indicators have total
conditional mass at most one. Multiplying the two separate mass
bounds proves \eqref{tr:history-weight}. For used pairs the physical
end experiments also have disjoint buffered supports, so their joint
law is the product used in the operator contribution. Arbitrary input
weights are bounded
pointwise by their total variation, as in
Lemma~\ref{tr:domination}; the number of switches on the input seam
does not enter the estimate.
To bound the remainder, run the inner exploration to its longest
allowed level. If it never reduces, it has paid a six-arm probability
over $n-O(1)$ dyadic levels. Otherwise let $j$ be its first reduction
level. If the reduction has fewer than four tips, its contribution
is zero. In the remaining case run the outer experiment as far as
\eqref{tr:used-pairs} allows, possibly through no additional level.
If it does not reduce in time, the two experiments together have
paid six-arm probabilities over at least $n-O(1)$ levels. Their
buffered supports remain disjoint. Summing the resulting bounds over
the at most $O((n+1)^2)$ possible terminal levels proves
\eqref{tr:unused}. The finitely many auxiliary localization failures
and near-coincidences of tips cost $o(1)$ for fixed $L$, uniformly by
Lemma~\ref{tr:domination}.
\end{proof}
At a four-tip inner frontier let $B$ and $W$ denote respectively the
black-join and white-join cap states. The pushed input message is
\begin{equation}
\alpha_j(v;H_i)(\delta_B-\delta_W),
\qquad |\alpha_j(v;H_i)|\le\|v\|_r,
\label{tr:inner-coefficient}
\end{equation}
where $H_i$ includes the inner history and its attachment to the input
seam. The coefficient is linear in $v$. Similarly, pushing
$\delta_B-\delta_W$ from an outer four-tip frontier to the output seam
gives a signed measure $q_k(H_o)$ satisfying
\begin{equation}
\|q_k(H_o)\|_{\TV}\le2.
\label{tr:outer-coefficient}
\end{equation}
Lemma~\ref{an:caps} says that the residual annulus sends the first
cap difference to the second multiplied by its through-transmission
probability. Thus the used-pair contribution has the form
\begin{equation}
\int \alpha_j(v;H_i)\,
\E_{\rm mid}\!\left[
\boldsymbol1_{G_{\rm aux}}t_r\mid H_i,H_o\right]
q_k(H_o)\,d\rho_j^{\rm in}(H_i)d\rho_k^{\rm out}(H_o),
\label{tr:integral}
\end{equation}
where $G_{\rm aux}$ denotes the additional middle screens and
$\E_{\rm mid}$ integrates the middle Poisson geometry conditional on
the two end histories. The probability $t_r$ already integrates the
fresh colors in the remaining face, conditional on all geometry.
The end laws are a product because their buffered supports are
disjoint. The conditional factor in square brackets still couples
the ends, and must not yet be factored.
On the auxiliary localization successes, the residual frontiers and
both $t_r$ and $T_r$ depend only on the auxiliary-cycle explorations and
the intervening independent geometry. Attachments to the original
seams enter only the signed coefficients. The error $|t_r-T_r|$ thus
has exactly the independent-region measurability required by
Lemma~\ref{tr:domination}.
By Lemmas~\ref{tr:admissible} and~\ref{tr:domination}, replace $t_r$ by
$T_r$ in \eqref{tr:integral} with $o(1)\|v\|_r$ error in output norm.
For fixed $n$, this error may be summed over all used pairs. The
frontiers themselves are still the actual graph cycles. Their
single-end conformal maps and capacities can therefore be used
directly in Proposition~\ref{sh:separated-ends}, without asserting
smoothness at contacts of a limiting boundary.
\subsection{Rank-one factorization and signed cancellation}
We now complete Proposition~\ref{tr:block}. An inner frontier at
level $j$ surrounds the center, stays inside radius comparable to
$a_j$, and reaches that radius at its tips. Its logarithmic capacity
$l_i$ is therefore comparable to $a_j$. An outer frontier at level
$k$ surrounds a disk of radius comparable to $b_k$ and has a point
at distance comparable to $b_k$; its conformal radius $l_o$ is
comparable to $b_k$. Write $y^0$ and $x^0$ for their single-end
switch angles. By \eqref{sh:rank-one},
\begin{equation}
T_r(H_i,H_o)=K\,U(H_i)V(H_o)
+O\big((a_j/b_k)^{\lambda+\sigma_1}\big),
\label{tr:separated-formula}
\end{equation}
where
\[
U(H_i)=l_i^\lambda J(y^0)^{1/3},
\qquad
V(H_o)=l_o^{-\lambda}J(x^0)^{1/3}.
\]
These factors depend on their own end histories only, and
\begin{equation}
|U(H_i)V(H_o)|
\le C L^{-\lambda}2^{\lambda(j+k)}.
\label{tr:factor-size}
\end{equation}
For the separated leading term, delete the extra middle screens.
This changes the integral by $o(1)\|v\|_r$ for fixed $L$: the screens
use independent interior variables and fail with probability $o(1)$,
while all weights at these fixed scales are bounded. Keep the original
seam screens and the local end screens. The remaining end experiments
now use disjoint Poisson supports for every used pair. Define the
scalar functionals and output messages
\[
u_j(v)=\int \alpha_j(v;H_i)U(H_i)\,d\rho_j^{\rm in}(H_i),
\qquad
v_k=\int V(H_o)q_k(H_o)\,d\rho_k^{\rm out}(H_o).
\]
The leading contribution of that pair is exactly $K u_j(v)v_k$.
The same definitions make sense separately for every level in each
finite list, whether or not a pair of levels has disjoint supports.
For such additional pairs we use the product of the two separate
integrals, not a claim about simultaneous experiments.
Set
\begin{equation}
M_1v=K\left(\sum_j u_j(v)\right)\left(\sum_k v_k\right).
\label{tr:rank-one-definition}
\end{equation}
This operator has rank at most one. By the separate six-arm bounds
and \eqref{tr:factor-size}, its norm is at most
\begin{equation}
C L^{-\lambda}
\sum_{j,k}2^{-(2+\tau-\lambda)(j+k)}
\le C L^{-\lambda}.
\label{tr:rank-one-size}
\end{equation}
The extra product terms introduced by allowing $j+k>n-d$ have norm
at most
\begin{equation}
C L^{-\lambda}
\sum_{j+k>n-d}2^{-(2+\tau-\lambda)(j+k)}
\le C(n+1)^2L^{-2-\tau}.
\label{tr:artificial-pairs}
\end{equation}
This numerical estimate requires no independence for overlapping
actual experiments.
Decrease $\sigma_1$ if necessary so that
$\lambda+\sigma_1<2+\tau$. The errors in
\eqref{tr:separated-formula}, summed using
Lemma~\ref{tr:tails}, have norm at most
\begin{equation}
C L^{-\lambda-\sigma_1}
\sum_{j+k\le n-d}
2^{-(2+\tau-\lambda-\sigma_1)(j+k)}+o(1)
\le C L^{-\lambda-\sigma_1}+o(1).
\label{tr:rank-error-sum}
\end{equation}
Together with \eqref{tr:unused} and
\eqref{tr:artificial-pairs}, this proves the first two estimates of
Proposition~\ref{tr:block}, with a smaller positive exponent saving,
in the mesh-first limit. All errors are measured in output total
variation, not merely after testing a fixed continuum event.
It remains to prove the stronger estimate for an even isotropic input
$v$. After the continuum replacement, delete the extra middle screens
as above. Only $T_r$ then depends on both ends; all other factors
belong to their separate, independently integrated end laws.
Rotate all inner end data, including the seam and the revealed
history. By equivariance of $v$, the coefficient
$\alpha_j(v;H_i)$ in \eqref{tr:inner-coefficient} is unchanged. Reverse
all colors of the inner data instead. The message is still unchanged
as a geometrically transformed signed measure, but the reference
vector $\delta_B-\delta_W$ changes sign. Thus
\begin{equation}
\alpha_j(v;\operatorname{rot}_\theta H_i)=\alpha_j(v;H_i),
\qquad
\alpha_j(v;\operatorname{flip} H_i)=-\alpha_j(v;H_i).
\label{tr:coefficient-symmetry}
\end{equation}
The inner end law is rotation and color-reversal invariant. The outer
measure factor is unaffected by either transformation of the inner
data. Labels for the four tips may be chosen independently of colors
using the auxiliary angular axis, and transported under rotations.
For each fixed outer history $H_o$, color reversal gives the identity
\begin{equation}
\begin{aligned}
&\int \alpha_j(v;H_i)T_r(H_i,H_o)\,d\rho_j^{\rm in}(H_i)\\
&\quad=\frac12\int \alpha_j(v;H_i)
\big[T_r(H_i,H_o)-T_r(\operatorname{flip}H_i,H_o)\big]
\,d\rho_j^{\rm in}(H_i).
\end{aligned}
\label{tr:flip-integral}
\end{equation}
Now average rotations of the inner data in the right side. Since
$\alpha_j$ and the inner law are rotation invariant, its contribution
is one half of the integral against the rotation average of
$T^+-T^-$, with its appropriate inner prescriptions. In particular
one must retain the sign; replacing this difference by an unsigned
four-arm event would lose the required exponent.
Equation~\eqref{sh:rotation-average} bounds the averaged difference
by $C(a_j/b_k)^{2+\sigma_2}$. The local end experiments and screens
can be chosen rotation and color-reversal invariant. Decrease
$\sigma_2$ so that $0<\sigma_2<\tau$. The used-pair contributions
are bounded in total variation by
\begin{equation}
C L^{-2-\sigma_2}
\sum_{j+k\le n-d}2^{-(\tau-\sigma_2)(j+k)}+o(1)
\le C L^{-2-\sigma_2}+o(1).
\label{tr:signed-sum}
\end{equation}
Adding the unused contribution \eqref{tr:unused} proves the desired
power strictly greater than two.
Finally choose $\delta>0$ smaller than all the positive savings just
obtained, decreasing it to absorb the polynomial factors in $n$.
For each fixed sufficiently large $n$, choose $r_0(2^n)$ so that every
$o(1)$ term is smaller than the required fixed power of $L$. This
proves \eqref{tr:block-size}--\eqref{tr:block-cancellation}.
Notice the order: the ratio is chosen first and the scale threshold
afterwards. No rate of convergence in Cardy's formula, in the
good-sequence extraction, or near a nonsimple limiting bank is used.
\subsection{Iteration and failed screens}
The block estimates have two consequences. The first uses the signed
symmetry estimate to control a Poisson insertion. The second uses the
rank-one approximation to compare two responses at different distant
boundaries.
\begin{corollary}[Fair-insertion message]
\label{tr:insertion}
There are $0<\nu<1$ and $C<\infty$ such that the following holds. Insert
a nucleus at the center of a cut, with an independent fair color. At
a seam of radius $s$, take the difference of the inside state laws
``with this insertion'' minus ``without this insertion,'' conditional
on the seam and with its screen success imposed. Its message
$I_s$ satisfies
\begin{equation}
\|I_s\|_s\le C s^{-2-\nu}
\label{tr:insertion-bound}
\end{equation}
for all sufficiently large $s$. The estimate remains valid in the
presence of fixed data outside the screened collar that do not enter
its inside. The seam tests and the selected cycle are those of the
base process, without the insertion.
\end{corollary}
\begin{proof}
Choose a ratio $L$ from Proposition~\ref{tr:block} so large that the
constant per block in \eqref{tr:block-cancellation} is absorbed by a
smaller power saving. Choose $s_*>r_0(L)$ sufficiently large. For
given $s$, use radii
\[
r_j=L^j r_0,\qquad 0\le j\le N,
\qquad r_N=s,\quad s_*\le r_00$, $s_0<\infty$, and a fixed ratio $L>1$ such that,
for $r\ge s_0$ and $s/r=L^N$, the transfer
\[
\mathcal M=M_{s/L,s}\cdots M_{r,Lr}
\]
with all intermediate seam successes imposed satisfies
\begin{equation}
\|\mathcal M u\wedge\mathcal M v\|_\pi
\le C(s/r)^{-2\lambda-\nu'}\|u\|_r\|v\|_r
\label{tr:wedge-bound}
\end{equation}
for any two zero-mass input messages $u,v\in\mathcal B_r$. Here
$u\wedge v=u\otimes v-v\otimes u$ and $\|\cdot\|_\pi$ is the
projective tensor norm. Fixed-factor unused intervals at the two
ends change only the constant. No assertion of this contraction
through a failed intermediate cut is made.
\end{corollary}
\begin{proof}
For one block write $M=M_1+E$ as in
\eqref{tr:block-rank}. Since $M_1$ has rank at most one,
$M_1\otimes M_1$ vanishes on antisymmetric tensors. On that subspace,
\[
\|M\otimes M\|
\le 2\|M_1\|\,\|E\|+\|E\|^2
\le C L^{-2\lambda-\delta}.
\]
Choose $L$ large enough to absorb $C$ into a smaller exponent saving
$\nu'>0$, simultaneously with its choice in
Corollary~\ref{tr:insertion}. Iterating the estimate and using
$\|u\wedge v\|_\pi\le2\|u\|_r\|v\|_r$ gives
\eqref{tr:wedge-bound}. The argument holds first for finite tensor
sums and then for their projective-norm completion. Ordinary
Markov pushes contract total variation, so fixed-factor omitted end
intervals affect only the constant after rounding to the ratio-$L$
grid.
\end{proof}
==== END A-Pivotal-Amplitude-for-Voronoi-Percolation-from-Cardys-Formula//05-transfer.tex ====
==== BEGIN A-Pivotal-Amplitude-for-Voronoi-Percolation-from-Cardys-Formula//06-amplitude.tex ====
\section{The intensity derivative and the pivotal amplitude}
\label{sec:amplitude}
The preceding section supplies two estimates with different roles.
Corollary~\ref{tr:insertion} makes the effect of a distant fair insertion
integrable, even after division by the central pivotal probability.
Corollary~\ref{tr:wedge} makes the normalized effect of a nearby insertion
almost independent of the size of the rectangle. Together they give a
summable error for the logarithmic derivative of $f$.
Throughout this section the Poisson intensity is one, unless otherwise
specified, and $\lambda=5/4$.
\subsection{Differentiating the intensity}
Let $X_R(\eta)$ be the indicator of a black left--right crossing of
$RQ_0$ for a colored point configuration $\eta$, with the closed-cell
convention of Theorem~\ref{thm:main}. If $0^{\rm b}$ and $0^{\rm w}$
denote an inserted black and white point at the origin, respectively, put
\[
H_R(\eta)
=X_R(\eta\cup\{0^{\rm b}\})-X_R(\eta\cup\{0^{\rm w}\}).
\]
Thus $H_R\in\{0,1\}$, and $f(R)=\E H_R(\eta)$ for the unit-intensity
fairly colored process. For $y\ne0$, write $y^{\rm f}$ for an independently
fairly colored inserted point and define
\begin{equation}\label{cl:kernel}
K_R(y)=\E\bigl[H_R(\eta\cup\{y^{\rm f}\})-H_R(\eta)\bigr].
\end{equation}
The expectation includes the extra color. Values at $y=0$ and at null
nongeneric insertion locations are immaterial to the integrals below.
In particular, $K_R$ is an insertion difference of a \emph{color}-pivotal
probability, not a probability of Poisson pivotality.
\begin{lemma}[Intensity differentiation]\label{cl:derivative}
The function $f$ is continuously differentiable on $(0,\infty)$. For
every $R>0$, $K_R$ is absolutely integrable and
\begin{equation}\label{cl:derivative-eq}
\frac R2 f'(R)=\int_{\R^2}K_R(y)\,dy.
\end{equation}
\end{lemma}
\begin{proof}
Let $\eta_t$ have intensity $t$ and fair colors. Euclidean scaling gives
\begin{equation}\label{cl:scaling-intensity}
G_R(t):=\E H_R(\eta_t)=f(\sqrt t\,R).
\end{equation}
We justify differentiation of the full-plane expectation before using
this identity. All the estimates in this paragraph are uniform for
$t$ in a compact subinterval of $(0,\infty)$.
For $n\ge n_0(R)$, let $H_{R,n}$ be the same test computed from the
points in $B(0,2^n)$, together with the central insertion. A locality
screen in a collar well inside $B(0,2^n)$ determines every cell meeting
$RQ_0$, including its intersections with the boundary. Consequently
$H_{R,n}=H_R$ outside an event of probability at most
$C_R\exp(-c_R4^n)$. The same screen gives
$H_{R,n+1}=H_{R,n}$. Finite-volume Poisson differentiation follows by
differentiating the absolutely convergent Poisson series; see also
\cite[Theorem~19.1]{LP}. Equivalently,
for a bounded function $F$ of the process in a bounded set $D$,
\begin{equation}\label{cl:poisson-score}
\frac{d}{dt}\E F(\eta_t\cap D)
=\E\left[F(\eta_t\cap D)
\left(\frac{N_t(D)}t-|D|\right)\right].
\end{equation}
Here $N_t(D)$ is the number of Poisson points in $D$.
Apply this to $F=H_{R,n+1}-H_{R,n}$ on $D=B(0,2^{n+1})$.
The score in parentheses has second moment $|D|/t$. Cauchy--Schwarz
therefore bounds the derivative by
$C_R2^n\exp(-c_R4^n)$. The differences of the expectations and of
their derivatives are uniformly summable. Hence $G_R$ is $C^1$ and
its derivative is the limit of the finite-volume derivatives.
The add-one version of finite-volume differentiation is
\[
\frac{d}{dt}\E H_{R,n}(\eta_t)
=\int_{B(0,2^n)}
\E\bigl[H_{R,n}(\eta_t\cup\{y^{\rm f}\})
-H_{R,n}(\eta_t)\bigr]\,dy.
\]
For fixed $y$ the integrand converges to its full-plane counterpart.
For $|y|\ge C R+C$, a screen surrounding $RQ_0$ and the origin, at
distance comparable to $|y|$ and strictly short of $y$, prevents the
insertion from changing any cell used by the test. Its failure
probability is at most $C_R e^{-c_R|y|^2}$. The screen can be taken
inside $B(0,2^n)$ whenever $y\in B(0,2^n)$ and $n$ is sufficiently
large; thus this is also a dominating bound for the finite-volume
integrands. On a fixed bounded set the bound $2$ suffices.
Dominated convergence proves absolute integrability and identifies
$G_R'(1)$ with the integral in \eqref{cl:derivative-eq}.
Equation~\eqref{cl:scaling-intensity} proves the asserted derivative
formula and, locally at each $R$, the $C^1$ assertion for $f$.
\end{proof}
\subsection{An integrable tail after normalization}
The exponential localization in Lemma~\ref{cl:derivative} is a
finite-scale statement. We need a bound uniform as $R$ grows, with
the small factor $f(R)$ retained. This is where the signed insertion
estimate is essential.
\begin{lemma}[Normalized insertion tail]\label{cl:tail}
There are constants $\xi>0$, $m_0<\infty$, and $C<\infty$ such that
for $m_0\le m\le R/100$,
\begin{equation}\label{cl:tail-eq}
\int_{|y|>m}|K_R(y)|\,dy
\le C f(R)\bigl(m^{-\xi}+R^{-\xi}\bigr).
\end{equation}
\end{lemma}
\begin{proof}
Use the exponent $0<\nu<1$ of Corollary~\ref{tr:insertion} and
the one-arm exponent $\beta>0$ from the critical inputs. All screens
and arm probes below have fixed-factor buffers. Independent probes
mean probes determined by disjoint sets of Poisson coordinates,
not unrestricted Voronoi events in disjoint planar regions.
We first explain how arm requirements can be multiplied by a signed
message estimate. The integrand in \eqref{cl:kernel} is a mixed
difference: one difference changes the central color, and the other
inserts the point at $y$. If this mixed difference is nonzero, changing
the central color changes a crossing for at least one setting of the
insertion, and changing the insertion changes a crossing for at least
one setting of the central color. A screened probe separated from
both changes reads the same base colors in all four configurations.
Thus the necessary-arm implications for a local change apply to
these common colors; see \cite[Section~2, ``Necessary arms for a
local change'']{V}. They apply even when the two crossing changes
occur in different configurations.
The conditional version is equally important. Every formal noncrossing
pairing can be drawn as disjoint wall arcs in a topological disk.
Coloring its complementary regions alternately realizes the prescribed
boundary runs and the pairing. Thus two formal cap states give two
planar fillings agreeing on every exterior probe; the deterministic
necessary-arm argument does not require Poisson geometry inside the
replaced disk. Fix a successful
cut about $y$, its seam, and all exterior variables. The exterior
test is now a function of the inside connection state. If a
necessary central or enclosing four-arm event does not occur,
the central black-minus-white test is zero for every such state.
If a necessary side or corner arm event does not occur, each
crossing test with the central color fixed is constant across
inside states. These are
the same planar necessary-arm implications, applied to two
possible cap states on the cut. The insertion message has zero
mass, so it annihilates the latter constants. Its conditional
answer is consequently bounded by its total variation norm times
the necessary probe indicators. Those indicators are measurable
outside the cut. Disjoint buffered supports then allow their
probabilities to be multiplied.
We use screened arm probes with failures allowed, whose probabilities
are still bounded by a constant times their intended arm bounds;
see the convention in Section~\ref{sec:inputs} and
\cite[Section~2, ``Buffered localization'']{V}.
Indeed, group failures by the largest failed radius $v$ and retain
the arm test starting a fixed factor beyond $v$, independently of
the failure. For a four-arm probe starting at $r$, the relevant
estimate is
\[
e^{-cv^2}A(C_0v,R)
\le C A(r,R)(v/r)^g e^{-cv^2}
\qquad(C_0v0$, and then choose $a>0$ sufficiently small relative
to $c_1$. Choose a cut about $y$ of radius $a t$,
a central four-arm probe from $b_*$ to $a t$,
and a four-arm probe surrounding both insertions from $a^{-1}t$
to $aR$.
Short or overlapping endpoint ranges are omitted at constant cost.
The buffers of these three constructions can be chosen disjoint.
On cut success, Corollary~\ref{tr:insertion} gives a bound
$Ct^{-2-\nu}$ for the insertion message. The central color
difference requires the first four-arm probe; transmission of a
change from the region containing both insertions to the crossing
requires the second. Thus the success contribution is at most
$Ct^{-2-\nu}A(b_*,t)A(t,R)$.
For failures, let $v$ be the largest failed radius about $y$, with
the initial radius comparable to $t$. If $v0$. If $\mathcal C_R$ is the set of the four
corners of $RQ_0$, set
\[
d(y)=\min\{\rho R,\max\{d_*,\dist(y,\partial(RQ_0))\}\},
\qquad
u(y)=\min\{\rho R,\max\{d_*,\dist(y,\mathcal C_R)\}\}.
\]
We take $R$ large enough that $d_*<\rho R$. Always
$d_*\le d(y)\le u(y)\le\rho R$; write $d=d(y)$ and $u=u(y)$.
The constants in the estimates may depend on $d_*$ and $\rho$.
There is a central four-arm probe up to radius $cR$, where $c$
is fixed and much smaller than $1/100$, disjoint from the other
regions used below. Its cost is at most $CA(b_*,R)$.
At an interior point $y$, use the insertion estimate on a cut of
radius a small fixed fraction of $d$. At the bottom cutoff a
constant bound suffices, and can be bounded by $Cd^{-2-\nu}$
because $d_*$ is fixed. At an exterior point with distance above
the bottom cutoff, successful screening at this scale leaves the
quad unchanged. Only screen failures contribute there, with a bound
exponential in $d^2$, which is no larger than $Cd^{-2-\nu}$.
If $u/d$ is larger than a sufficiently large constant, the closest
part of the boundary is a straight side. A crossing change then
requires three alternating free arms in a half-plane probe centered
at the projection onto that side, from radius $Cd$ to radius $cu$.
Its cost is at most $C(d/u)^2$. If the projection is at a corner,
the two distances are comparable and this probe is unnecessary.
When $u$ is uncapped and is a sufficiently small fraction of $R$,
retain a one-arm probe centered at the nearest corner from radius
$Cu$ to radius $cR$. Its cost is at most $C(u/R)^\beta$.
For $u$ capped above, this factor is a fixed positive constant,
so the corresponding probe can be omitted. These are precisely
the local-change arm implications for the unwired, closed-cell
crossing convention. They also cover a modified cell meeting a
side or a corner.
The insertion cut, the side probe, the corner probe, and the
central probe can be given disjoint buffered supports. To arrange
this, first fix the central radius $cR$, then choose the distance
cap $\rho R$ much smaller. A corner probe is used only in a
corner neighborhood, far from the center. Fixed multiples are
lost between consecutive probes, which changes only constants.
To include failures, choose a sufficiently small fixed $c_2>0$.
For a largest failed radius $v10R$ an agreement screen between the test rectangle and
$y$ gives $|K_R(y)|\le Ce^{-c|y|^2}$. Its integral is at most
$Ce^{-cR^2}$. The polynomial lower bound for $f$ following from
\eqref{in:comparison} absorbs this into $Cf(R)R^{-\xi_0}$.
Combining this with \eqref{cl:bulk-integral} and
\eqref{cl:boundary-integral}, and decreasing the exponent, proves
\eqref{cl:tail-eq}.
\end{proof}
\subsection{Comparing the normalized derivatives}
The tail estimate permits us to discard insertions far from the
origin. For the remaining insertions we use the same interior
messages in two different rectangles. Rank-one approximation then
controls a determinant, so that no unknown leading factor needs
to be identified.
\begin{lemma}[Two-size determinant]\label{cl:determinant}
Let $\nu'>0$ be the exponent in Corollary~\ref{tr:wedge}.
There are constants $C,c>0$ such that, for sufficiently large $m$,
$100m\le R\le R'\le2R$, and almost every $0<|y|\le m$,
\begin{equation}\label{cl:determinant-eq}
\bigl|K_R(y)f(R')-K_{R'}(y)f(R)\bigr|
\le C(m/R)^{2\lambda+\nu'}+Ce^{-cm^2}.
\end{equation}
The constants are independent of the distance from $y$ to the origin.
\end{lemma}
\begin{proof}
Take concentric cuts about the origin, starting at radius $10m$
and ending at a radius comparable with a small fixed fraction of
$R$, with consecutive radii in ratio $L$. Round the final radius
down to the last such scale. Its ratio to $R$ is bounded below
by a positive constant depending only on the already fixed $L$.
All cut collars lie strictly inside both rectangles and outside
both inserted points. If necessary, enlarge the fixed lower
bound on $R/m$; the remaining bounded ratios follow by increasing
$C$, since all four scalar quantities in the determinant are bounded.
First restrict every test to success of every cut screen, with
the screens evaluated on the common base process. The probability
discarded is bounded by
\[
C\sum_{j\ge0}\exp\bigl(-cm^2L^{2j}\bigr)
\le Ce^{-c'm^2}.
\]
At the first cut let $a$ be the signed connection-state message
obtained by changing the central color. Let $b_y$ be the
difference of this message with and without the extra fair point
at $y$. Both have zero mass conditional on each seam, and
their total variation norms are bounded by $2$ and $4$,
respectively. They depend on neither $R$ nor $R'$: on screen
success their construction uses only the common interior
Poisson variables and the first seam. In particular this
description does not require disjoint neighborhoods of $0$ and $y$.
Let $T$ be the composed transfer through the intervening cuts.
The exterior crossing tests in $RQ_0$ and $R'Q_0$ define bounded
linear functionals $\ell_R$ and $\ell_{R'}$ at the final cut.
The four restricted expectations are
\[
\ell_R(Ta),\quad \ell_{R'}(Ta),\quad
\ell_R(Tb_y),\quad \ell_{R'}(Tb_y).
\]
Their determinant is the evaluation of $T^{\otimes2}$ on
$b_y\otimes a-a\otimes b_y$ by
$\ell_R\otimes\ell_{R'}$. Corollary~\ref{tr:wedge} therefore
bounds it by $C(m/R)^{2\lambda+\nu'}$.
Restoring the discarded events changes the determinant by at
most $Ce^{-cm^2}$, because each scalar factor is bounded.
This proves \eqref{cl:determinant-eq}.
\end{proof}
\begin{proposition}[Summable logarithmic error]\label{cl:log-derivative}
There are constants $\alpha>0$ and $C<\infty$ such that
\begin{equation}\label{cl:log-derivative-eq}
\left|\frac{Rf'(R)}{f(R)}+\lambda\right|
\le CR^{-\alpha}
\end{equation}
for all sufficiently large $R$.
\end{proposition}
\begin{proof}
Set $g(R)=Rf'(R)/f(R)$, which is defined and continuous for
large $R$ by Lemma~\ref{cl:derivative} and
\eqref{in:comparison}. We first prove a uniform estimate on
each interval $[R,2R]$. Fix
\[
\zeta=\frac{\nu'}{4(2+2\lambda+\nu')},\qquad
\eta=\frac{\nu'}8,\qquad m=R^\zeta.
\]
The exponent estimate \eqref{in:exponent-eq} implies
$f(s)\ge s^{-\lambda-\eta}$ for all sufficiently large $s$.
For $R\le R'\le2R$, divide \eqref{cl:determinant-eq} by
$f(R)f(R')$ and integrate over $|y|\le m$. The result is
\begin{align}
\left|\int_{|y|\le m}\frac{K_R(y)}{f(R)}\,dy
-\int_{|y|\le m}\frac{K_{R'}(y)}{f(R')}\,dy\right|
&\le C R^{2\lambda+2\eta}m^2
\bigl[(m/R)^{2\lambda+\nu'}+e^{-cm^2}\bigr]\notag\\
&\le C R^{-\nu'/2}.
\label{cl:normalized-near}
\end{align}
Indeed the power in the first term is exactly
\[
-\nu'+2\eta+\zeta(2+2\lambda+\nu')=-\nu'/2,
\]
and the exponential term is smaller. For large $R$, the chosen
$m$ satisfies all the scale restrictions of
Lemmas~\ref{cl:tail} and~\ref{cl:determinant}.
Lemma~\ref{cl:tail} bounds each complementary normalized integral
by $C R^{-\zeta\xi}$. Since
$g(R)=2\int K_R(y)/f(R)\,dy$ by
\eqref{cl:derivative-eq}, we obtain
\begin{equation}\label{cl:dyadic-oscillation}
\sup_{R\le R'\le2R}|g(R')-g(R)|\le CR^{-\alpha},
\qquad
\alpha=\min\{\nu'/2,\zeta\xi\}>0.
\end{equation}
The values $g(2^nR_0)$ form a Cauchy sequence, because the
successive errors in \eqref{cl:dyadic-oscillation} are summable.
The same estimate between dyadic points shows that $g(R)$ has
a finite limit $\gamma$ as $R\to\infty$, and summing along
$R,2R,4R,\ldots$ gives
\[
|g(R)-\gamma|\le C\sum_{j\ge0}(2^jR)^{-\alpha}
\le C'R^{-\alpha}.
\]
It remains to identify this limit. Integration yields
\[
\log f(R)-\log f(R_0)=\int_{R_0}^R g(s)\,\frac{ds}s.
\]
Dividing by $\log R$ shows that
$\log f(R)/\log R\to\gamma$. By \eqref{in:exponent-eq} the
same limit is $-\lambda$. Thus $\gamma=-\lambda$, proving
\eqref{cl:log-derivative-eq}.
\end{proof}
\subsection{Completion of the normalization}
\begin{proof}[Proof of Theorem~\ref{thm:main}]
By Proposition~\ref{cl:log-derivative},
\[
\frac{d}{dR}\log\bigl(R^\lambda f(R)\bigr)=O(R^{-1-\alpha}).
\]
The right side is integrable at infinity. Since $f(R)>0$ for
large $R$, the logarithm has a finite real limit. Consequently
\begin{equation}\label{cl:amplitude}
R^{5/4}f(R)\longrightarrow a\in(0,\infty).
\end{equation}
Positivity and finiteness follow from convergence of the
\emph{logarithm}, rather than merely boundedness of the normalized
probabilities. In fact the argument also gives
$R^{5/4}f(R)=a(1+O(R^{-\alpha}))$.
Recall that $S_\eps=f(1/\eps)$,
$m_\eps=\eps^{-2}$, and
$q_\eps=(\E N_\eps(Q_0))^{-1}$.
The calibration limits \eqref{in:calibration-eq} are
\[
m_\eps q_\eps S_\eps\longrightarrow c\in(0,\infty),
\qquad
q_\eps\E N_\eps\longrightarrow B\in(0,\infty).
\]
Equation~\eqref{cl:amplitude} gives
$S_\eps\sim a\eps^{5/4}$, hence
$q_\eps\sim(c/a)\eps^{3/4}$. It follows that
\[
\eps^{3/4}\E N_\eps\longrightarrow \frac{Ba}{c}
=:c_V\in(0,\infty).
\]
Here $N_\eps$ counts color-pivotal sites for the original unwired
unit-square event. The Poisson insertion was used only to
differentiate $f$; it has not changed the pivotal count in this
last formula. Taking reciprocals proves the equivalent assertion
for the near-critical scale.
\end{proof}
==== END A-Pivotal-Amplitude-for-Voronoi-Percolation-from-Cardys-Formula//06-amplitude.tex ====
==== BEGIN A-Pivotal-Amplitude-for-Voronoi-Percolation-from-Cardys-Formula//lobes.tex ====
\begin{figure}[tb]
\centering
\begin{tikzpicture}[font=\footnotesize,>=Latex,line cap=round,
bank/.style={very thick},
barrier/.style={densely dashed,gray!80},
fluid/.style={fill=blue!8}]
\begin{scope}[xshift=0.3cm]
\fill[blue!8] (0,0) circle (2.65);
\fill[black!9]
(2,0) .. controls (1.25,.25) and (.25,1.25) .. (0,2)
.. controls (-.25,1.25) and (-1.25,.25) .. (-2,0)
.. controls (-1.25,-.25) and (-.25,-1.25) .. (0,-2)
.. controls (.25,-1.25) and (1.25,-.25) .. cycle;
\draw[barrier] (0,0) circle (2);
\draw[bank]
(2,0) .. controls (1.25,.25) and (.25,1.25) .. (0,2);
\draw[bank,gray!55]
(0,2) .. controls (-.25,1.25) and (-1.25,.25) .. (-2,0);
\draw[bank]
(-2,0) .. controls (-1.25,-.25) and (-.25,-1.25) .. (0,-2);
\draw[bank,gray!55]
(0,-2) .. controls (.25,-1.25) and (1.25,-.25) .. (2,0);
\foreach \p in {(2,0),(0,2),(-2,0),(0,-2)}
\fill \p circle (2pt);
\draw[gray!75] (0,0) circle (.58);
\node[align=center,font=\scriptsize] at (0,0) {starting\\side};
\node at (1.15,1.15) {$L_1$};
\node at (-1.15,1.15) {$L_2$};
\node at (-1.15,-1.15) {$L_3$};
\node at (1.15,-1.15) {$L_4$};
\node[align=center] at (0,2.97) {unqueried annular back};
\draw[->,thin] (.78,2.87)--(1.15,2.18);
\node[align=left,anchor=west] at (2.8,.95)
{four-tip\\frontier};
\draw[->,thin] (2.78,.77)--(1.43,.30);
\node[align=left,anchor=west] at (2.8,-.80)
{open attachment\\interval};
\draw[->,thin] (2.78,-.70)--(1.74,-.97);
\node[align=center] at (0,-3.05)
{Dashed circle: stopping barrier.\\
Its open intervals lie inside the glued domain.};
\end{scope}
\begin{scope}[xshift=8.85cm,yshift=.20cm]
\node[align=center] at (0,2.28) {Two distinct banks at a contact};
\fill[blue!8]
(-1.55,1.70)--(1.55,1.70)--(1.55,.85)
.. controls (.85,.85) and (.50,0) .. (0,0)
.. controls (-.50,0) and (-.85,.85) .. (-1.55,.85)--cycle;
\fill[blue!8]
(-1.55,-1.70)--(1.55,-1.70)--(1.55,-.85)
.. controls (.85,-.85) and (.50,0) .. (0,0)
.. controls (-.50,0) and (-.85,-.85) .. (-1.55,-.85)--cycle;
\draw[bank]
(-1.55,.85) .. controls (-.85,.85) and (-.50,0) .. (0,0)
.. controls (.50,0) and (.85,.85) .. (1.55,.85);
\draw[bank,gray!55]
(-1.55,-.85) .. controls (-.85,-.85) and (-.50,0) .. (0,0)
.. controls (.50,0) and (.85,-.85) .. (1.55,-.85);
\fill (0,0) circle (2.2pt);
\node at (0,1.30) {first access};
\node at (0,-1.30) {second access};
\draw[->,thin] (0,.96)--(0,.20);
\draw[->,thin] (0,-.96)--(0,-.20);
\node[align=center] at (0,-2.30)
{The contact is boundary,\\not a gluing interval.};
\end{scope}
\end{tikzpicture}
\caption{The decomposition at an inner four-tip frontier. The four
monochromatic frontier arcs, drawn alternately black and gray, bound
Jordan lobes $L_1,\ldots,L_4$ with the stopping barrier. Each lobe is
attached to the untouched annular back along an open barrier interval;
the common shading denotes the resulting unqueried domain. The starting
side remains in the complement. At the other end the construction is
reversed. The inset records two accesses at a possible contact between
different banks: the contact is not added to the fluid and does not join
the accesses. All curves are schematic. Actual banks may be rough and
may touch each other, although each individual frontier arc is simple.}
\label{fig:frontier-lobes}
\end{figure}
==== END A-Pivotal-Amplitude-for-Voronoi-Percolation-from-Cardys-Formula//lobes.tex ====
==== BEGIN A-Pivotal-Amplitude-for-Voronoi-Percolation-from-Cardys-Formula//paper.tex ====
\newcommand{\DoNotLoadEpstopdf}{}
\documentclass[11pt]{article}
\usepackage[T1]{fontenc}
\usepackage{lmodern}
\usepackage[margin=1.05in]{geometry}
\usepackage{amsmath,amssymb,amsthm,mathtools}
\usepackage{microtype}
\usepackage{enumitem}
\usepackage{tikz}
\usetikzlibrary{arrows.meta,patterns,calc}
\usepackage{booktabs}
\usepackage{xurl}
\usepackage[hidelinks]{hyperref}
\hypersetup{pdftitle={A Pivotal Amplitude for Voronoi Percolation from Cardy's Formula},pdfauthor={OpenAI}}
\newtheorem{theorem}{Theorem}[section]
\newtheorem{proposition}[theorem]{Proposition}
\newtheorem{lemma}[theorem]{Lemma}
\newtheorem{corollary}[theorem]{Corollary}
\theoremstyle{definition}
\newtheorem{definition}[theorem]{Definition}
\newtheorem{assumption}[theorem]{Assumption}
\theoremstyle{remark}
\newtheorem{remark}[theorem]{Remark}
\newcommand{\R}{\mathbb R}
\newcommand{\C}{\mathbb C}
\newcommand{\E}{\mathbb E}
\newcommand{\Pp}{\mathbb P}
\newcommand{\eps}{\varepsilon}
\newcommand{\TV}{\mathrm{TV}}
\DeclareMathOperator{\Var}{Var}
\DeclareMathOperator{\dist}{dist}
\DeclareMathOperator{\supp}{supp}
\DeclareMathOperator{\rank}{rank}
\numberwithin{equation}{section}
\setlist[enumerate]{itemsep=3pt,topsep=5pt}
\setlist[itemize]{itemsep=3pt,topsep=5pt}
\emergencystretch=1em
\title{A Pivotal Amplitude for Voronoi Percolation\newline from Cardy's Formula}
\author{OpenAI}
\date{October 5, 2026}
\begin{document}
\maketitle
\begin{abstract}
Taking Cardy's conformal crossing formula for critical planar
Poisson--Voronoi percolation in every bounded Jordan quadrilateral as an
input, we prove that the expected number of color-pivotal cells for a
unit-square crossing is asymptotic to a positive constant times
$\eps^{-3/4}$, where the point intensity is $\eps^{-2}$.
No rate of convergence in Cardy's formula is required.
\end{abstract}
\setcounter{tocdepth}{1}
\tableofcontents
\clearpage
\input{sections/00-introduction}
\input{sections/01-inputs}
\input{sections/02-annuli}
\input{sections/03-spectrum}
\input{sections/04-shape}
\input{sections/05-transfer}
\input{sections/06-amplitude}
\input{references}
\end{document}
==== END A-Pivotal-Amplitude-for-Voronoi-Percolation-from-Cardys-Formula//paper.tex ====
==== BEGIN A-Pivotal-Amplitude-for-Voronoi-Percolation-from-Cardys-Formula//references.tex ====
\begin{thebibliography}{99}
\bibitem{BL}
H.~J. Brascamp and E.~H. Lieb,
On extensions of the Brunn--Minkowski and Pr\'ekopa--Leindler theorems,
including inequalities for log concave functions, and with an application
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